Symbol * denote to be one of the operations add, subtract, multiply, o

But doesn't the question asks the symbol to be one of the operations? Going by that answer should be c

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VeritasKarishma plz solve this question

Is \((6*2)*4=6*(2*4)\)?

If the symbol is 'add' or 'multiply', the brackets become irrelevant. The two sides will be equal.
But if it is subtract or divide, the brackets play a role in deciding what the final answer will be.

So the question boils down to "Does the symbol denote add/multiply?"

1) \(3*2>3\)

If the symbol were subtract or divide,
3 - 2 < 3
and 3/2 < 3

So the symbol MUST be add or multiply. Then the answer is yes. Sufficient.

2) \(3*1=3\)

Here, the symbol could be multiply or divide because in both cases it holds.
3 * 1 = 3
3/1 = 3

Then can we say whether the symbol is add/multiply? No. It may be multiply or it may be divide. Not sufficient.

Answer (A)

Can you help me understand in this way it will have two options for the symbol? but dnt we need one as the ques says symbol * denote to be one of the operations, add, subtract, multiply or divide?

Kshitij609 & ManyataM

It means that * stands for only 1 operation during a single instance, but can be another operation at another instance E.g. S1 tells us that * could be addition or multiplication. Now \((6 * 2) * 4 = 6 * (2 * 4)\) can be solved once by replacing * with + i.e. \((6 + 2) + 4 = 6 + (2 + 4)\) and another time by replacing * with * i.e. \((6 * 2) * 4 = 6 * (2 * 4)\), but you cannot combine them at the same time i.e. \((6 + 2) * 4 = 6 * (2 + 4)\)

So by stating Symbol * denotes one of the operations its preventing you from combining multiple operations in a single instance, but you are free to apply different operations at different instances

Hope its clear!

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