Competition Mode Question Ted is now 12 years older than Leila, who is 2 years older than Sheila. If in 20 years, Ted will be 20% older than Sheila, how old is Leila now? A. 40 B. 48 C. 50 D. 52 E. 64

T=12+L L=S+2, S=L-2 T+20=6/5(S+20) 5T-6S=120-100 5(12+L)-6(L-2)=20 60-L+12=20 L=72-20=52 Ans (D)

Ted is now 12 years older than Leila, who is 2 years older than Sheila. If in 20 years, Ted will be 20% older than Sheila, how old is Leila now? A. 40 B. 48 C. 50 D. 52 E. 64 T = 12+L L=S+2 20 years, T+20=1/5(S+20)+(S+20) on solving, we get S=50, so, L=52 Ans D

Teds age = Leila Age+12 = (Sheila Age + 2) +12 = Sheila Age + 14 Let Age of ted be T, Leila be L, Sheila be S ;(present age) so T = S + 14 after 20 years Age of Ted = T + 20 =S +14+20=S+34 Age of Sheila= S+20 Condition is (T + 20) = 20% older than sheila => S +34 = (S+20) + 20% of (S+20) => S +34 = (S+20) + 1/5(S+20) => S +34 =(S+20)(1+1/5) = 6/5*(S+20) =6/5 * S+ 24 => 6/5*S - s=34-24 => 1/5 * S= 10 => S=10*5 = 50 Therefore Leila's present Age = s+2=50+2=52

ted= x+14 , Leila = x+2 , sheila= x after 20 years , lets add 20 ted= x+14+20 , sheila= x+20 x+34/x+20=120/100 100x+3400=120x+2400 20x=1000 x=50 so Leila age will be : x+2=50+2=52 ANS:D

T = L + 12 L = S + 2 In 20 years, T+20 = 1.2(S+20) L+12+20=1.2(L-2+20) L+32=1.2L+21.6 L=10.4/1.2 L=52 Answer is D

Now _____ T = 12 + L L = 2 + S +20 yrs from Now ________________ T + 20 = (120%) (S + 20) T + 20 = (6/5) (S + 20) 5T + 100 = 6S + 120 5T - 6S = 20 ------- (equation 1) Plug In to equation 1: T = 12 + L ---- and----- S = L - 2 5(12 + L) - 6(L - 2) = 20 60 + 5L - 6L + 12 = 20 72 - L = 20 L = 52 Lelia is 52 years old Now. -D-

Given: Ted is now 12 years older than Leila, who is 2 years older than Sheila. Asked: If in 20 years, Ted will be 20% older than Sheila, how old is Leila now? Let the ages of Ted, Leila & Sheila be t, l & s respectively Ted is now 12 years older than Leila, who is 2 years older than Sheila. t = l + 12 l = s + 2 t = l + 12 = s + 14 In 20 years, Ted will be 20% older than Sheila t + 20 = 1.2 (s + 20) s + 34 = 1.2s + 24 .2s = 10 s = 10/.2 = 50 l = s+2 = 52 years Leila is 52 years old now IMO D

If Leilla is x years old now, Ted will be x+12 If Sheila is y Leilla will be y+2 years old now. In 20 years, x + 12+20 = 1.2(x + 18) x + 32 = 1.2x + 21.6 0.2x = 10.4 x = 52. GMAT quant instructor Lagos Nigeria Posted from my mobile device

Ted is now 12 years older than Leila, who is 2 years older than Sheila. If in 20 years, Ted will be 20% older than Sheila, how old is Leila now? Let the present age of Ted, Leila, and Sheila be denoted by t, l, and s respectively => t = l + 12 => l = s + 2 Using 1 and 2 we will eliminate l => t = s + 14 Also, => t + 20 = 1.2 ( s + 20 ) => s + 34 = 1.2 (s + 20 ) => 0.2s = 10 => s = 50 therefore l = s + 2 = 52 Hence answer

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