kidderek wrote:

tikpaklong wrote:

sorry about the answer choices...yes the official answer is 2^9. Can you guys explain? I'd appreciate it. Thanks.

Basically, the question asks how many different outcomes are there if you toss up 10 coins. The answer to that is 2^10

But since the third coin is heads, we divide the total number of combinations by 2, thus (2^10)/2 = 2^9

OR

How many different outcomes can there be for the 9 remaining coins if the third one is heads? 2^9

Great explanation, I am not new to the forum, but I have not been paticipating in the math section...so I am not familiar with the symbals...

Question: 2^9, does this mean 2 to the 9th power??? I am assuming it is...