Pragnya87 wrote:

Zarrolou wrote:

Condition: at least one in each, at most five with equal number.

To minimize the overall number, we have to place 1 in five buckets.

\(1-1-1-1-1-...\)

Condition: no other two have the same number of balls, hence we must complete the sequence like this

\(1-1-1-1-1-2-3-4-5\) => \(Tot=19\)

HI Thanks for your explanation..To understand a little bit more, can you please tell me how did u approach on the second condition?

From here, we have 4 empty slots

\(1-1-1-1-1-?-?-?-?\)

Can we put 0 balls in the 6th slot ? No because there must be at least one in each.

Can we put 1 ball again in the 6th slot ? No because at most five have the same number of balls.

Can we put 2 balls in the 6th slot ? Yes

From now on you can repeat the reasoning for the 7th slot:

Can we put 0 balls in ? No because there must be at least one in each.

Can we put 1 ball again? No because at most five have the same number of balls.

Can we put 2 balls in ? No, SECOND CONDITION

no other two have the same number of ballsCan we put 3 balls in ? Yes

and so on...

At the end we have this: \(1-1-1-1-1-2-3-4-5\) => \(Tot=19\)

Hope I've explained myself well

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