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06 Mar 2020, 04:49
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The amount of time that three people worked on a certain project was in the ratio of 2 : 3 : 5. If the project took 110 hours, what is the difference between the number of hours worked by the person who worked for the longest time and the person who worked for the shortest time?
(A) 22
(B) 33
(C) 44
(D) 55
(E) 66
(A) 22
(B) 33
(C) 44
(D) 55
(E) 66
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06 Mar 2020, 05:01
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Bunuel
The amount of time that three people worked on a certain project was in the ratio of 2 : 3 : 5. If the project took 110 hours, what is the difference between the number of hours worked by the person who worked for the longest time and the person who worked for the shortest time?
(A) 22
(B) 33
(C) 44
(D) 55
(E) 66
(A) 22
(B) 33
(C) 44
(D) 55
(E) 66
total time worked on project = 10*x = 110; x = 11.
difference between longest time - shortest time = 5*x -2*x = 3*x = 33
Ans: B
yashikaaggarwal
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06 Mar 2020, 05:05
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The total working hours is 110
The ratio in which A:B:C work 2:3:5 can be written as:
A: 110*2/5 = 44
B: 110*3/5 = 66
C: 110*5/5 = 110
(As all did worked for full 110 hours but A and B together did work in 2:3 in 44:66 hours as done by C in 110 hours)
So the difference between the longest time taker and the shortest time taker is 110-44 which is 66. So OA is E.
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The ratio in which A:B:C work 2:3:5 can be written as:
A: 110*2/5 = 44
B: 110*3/5 = 66
C: 110*5/5 = 110
(As all did worked for full 110 hours but A and B together did work in 2:3 in 44:66 hours as done by C in 110 hours)
So the difference between the longest time taker and the shortest time taker is 110-44 which is 66. So OA is E.
Posted from my mobile device
