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25 Dec 2017, 01:13
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C
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Difficulty:
25%
(medium)
Question Stats:
79% (01:45) correct
21%
(01:24)
wrong
based on 121
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The amounts of time that three executives worked on a special campaign are in the ratio of 1 to 2 to 5. If they worked an average (arithmetic mean) of 44 hours per person on the campaign, how many hours did the executive who worked the longest spend on the campaign?
A. 220
B. 132
C. 82.5
D. 75
E. 27.5
A. 220
B. 132
C. 82.5
D. 75
E. 27.5
25 Dec 2017, 01:58
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Bunuel
As we have the ratios and the total, we'll just calculate.
This is a Precise approach.
The three executives together worked for a total of 1 + 2 + 5 = 8 'ratio units'.
Snce they worked for an average of 44 hours, they worked for a total of 44*3 = 132 hours.
Then each ratio unit is worth 132/8 = (80+40+12)/8 = 10 +5 + 1.5 = 16.5 hours.
Therefore the employee who worked the longest (for 5 ratio units) worked for 5*16.5 = 82.5 hours.
(C) is our answer.
24 Jan 2021, 19:20
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e1:e2:e3 = 1:2:5 = 1x:2x:5x
1x + 2x + 5x = 8x <---Total amount of time spent by all three
Avg = 44 = 8x / 3
x = 16.5
5(16.5) = 82.5
Answer is C.
1x + 2x + 5x = 8x <---Total amount of time spent by all three
Avg = 44 = 8x / 3
x = 16.5
5(16.5) = 82.5
Answer is C.
