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Re: The angles in a triangle are x, 3x, and 5x degrees. If a, b, and c are [#permalink]
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VERBAL1 wrote:
The angles in a triangle are \(x\), \(3x\), and \(5x\) degrees. If \(a\), \(b\) and \(c\) are the lengths of the sides opposite to angles \(x\), \(3x\), and \(5x\) respectively, then which of the following must be true?

I. \(c \gt a+b\)

II. \(c:a:b=10:6:2\)

III. \(c^2 \gt a^2+b^2\)


A. I and III only
B. II and III only
C. I only
D. II only
E. III only

M08-31


Solution:

Since the sum of the measures of the angles in a triangle is 180 degrees, we can create the equation:

x + 3x + 5x = 180

9x = 180

x = 20

Therefore, the measures of the angles are 20, 60, and 100 degrees. We see that the triangle is an obtuse triangle, which means the square of the length of the longest side of a triangle is greater than the sum of the squares of the lengths of the other two sides. So III is true. However, I is not true since the length of any side of a triangle is always less than the sum of the lengths of the other two sides. II is not true, either, since the lengths of the sides of a triangle (with the exception of the equilateral triangle) do not have the same ratio as the measures of the angles opposite them.

Answer: E
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Re: The angles in a triangle are x, 3x, and 5x degrees. If a, b, and c are [#permalink]
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Re: The angles in a triangle are x, 3x, and 5x degrees. If a, b, and c are [#permalink]
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