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06 Sep 2018, 00:37
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D
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Difficulty:
15%
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Question Stats:
89% (01:02) correct
11%
(01:41)
wrong
based on 42
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The area of a rectangular playground is 192 square meters. What is the perimeter of the playground?
(1) The length of the playground is three times the width of the playground .
(2) If the width of the playground were doubled, then the ratio of the length to the width would be 3 : 2
(1) The length of the playground is three times the width of the playground .
(2) If the width of the playground were doubled, then the ratio of the length to the width would be 3 : 2
06 Sep 2018, 03:31
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[quote=]The area of a rectangular playground is 192 square meters. What is the perimeter of the playground?
(1) The length of the playground is three times the width of the playground .
(2) If the width of the playground were doubled, then the ratio of the length to the width would be 3 : 2[/quote]
let the length be L and the Width W
We know \(L*W=192\).......................(i)
\(Perimeter=2(L+W)\)........................(ii)
Statement 1: The length of the playground is three times the width of the playground
This implies, \(L=3W\).......................(iii)
We can substitute L in (i) and solve the quadratic to calculate \(W\)
and using (ii), we can get L and hence calculate the Perimeter using (iii)
Sufficient.
Statement 1: If the width of the playground were doubled, then the ratio of the length to the width would be 3 : 2
This implies, \(W'(New Width)=2W\)
Therefore, \(\frac{L}{2W} = \frac{3}{2}\)
We can substitute either of L or W from this equation into (i) to solve the quadratic and again use the above equation to calculate the other variable.
Using (ii), we can calculate the Perimeter.
Sufficient.
Answer: D
(1) The length of the playground is three times the width of the playground .
(2) If the width of the playground were doubled, then the ratio of the length to the width would be 3 : 2[/quote]
let the length be L and the Width W
We know \(L*W=192\).......................(i)
\(Perimeter=2(L+W)\)........................(ii)
Statement 1: The length of the playground is three times the width of the playground
This implies, \(L=3W\).......................(iii)
We can substitute L in (i) and solve the quadratic to calculate \(W\)
and using (ii), we can get L and hence calculate the Perimeter using (iii)
Sufficient.
Statement 1: If the width of the playground were doubled, then the ratio of the length to the width would be 3 : 2
This implies, \(W'(New Width)=2W\)
Therefore, \(\frac{L}{2W} = \frac{3}{2}\)
We can substitute either of L or W from this equation into (i) to solve the quadratic and again use the above equation to calculate the other variable.
Using (ii), we can calculate the Perimeter.
Sufficient.
Answer: D
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