seeker14 wrote:
sreejitb wrote:
Semi Perimeter of First Triangle = (6 + 8 + 10)/2 = 12
Area = \sqrt{S (S-6)(S-8)(S-10)} = 24.
Semi Perimeter of First Triangle = (3 + 4 + 5)/2 = 6
Area = \sqrt{S (S-3)(S-4)(S-5)} = 6.
Ratio of Areas = 24/6 = 4.
Hence, C.
Could you please explain the use of the formula in detail? Because I think this is a better use of we do not know what side of the triangle is base and what is the height. In this case we had popular combinations of sides.
This is what is called the "Heron's Formula". This formula gives us the area of a triangle when the length of all three sides are known.
Let the 3 sides of a triangle be of length a, b and c.
Hence perimeter (P) = a + b + c
Semi Perimeter (P/2) = (a + b + c)/2. Say "S".
Hence Area (A) of the triangle will be:
A = \sqrt{S(S-a) (S-b) (s-c)}