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The area of square region S is what percent greater than

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The area of square region S is what percent greater than [#permalink]

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New post 15 Apr 2017, 17:53
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The area of square region S is what percent greater than the area of square region T?

1) The length of a side of square S is 10% greater than the length of a side of square T.

2) The length of a side of square S is 22 and the length of a side of square T is 20.

OA
D.
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Re: The area of square region S is what percent greater than [#permalink]

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New post 15 Apr 2017, 19:12
kimbercs wrote:
The area of square region S is what percent greater than the area of square region T?

1) The length of a side of square S is 10% greater than the length of a side of square T.

2) The length of a side of square S is 22 and the length of a side of square T is 20.

OA
D.



Let the side of 1st sq =x
then side of 2nd one is = 1.1x
thus thier respective area := x^2 and (1.1x)^2
let area of 2nd sq. be A % greater thus we can calculate as

(1.1x)^2 = x^2 (1+A/100)
so A can be calculated

suff

(2) let area of 2nd sq. be A % greater thus we can calculate as

(22)^2 = 20^2 (1+A/100)
so A can be calculated
(Note:- option 2 is similar to option 1 , as 22 is 10% greater than 20)
suff..

Ans D
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Re: The area of square region S is what percent greater than [#permalink]

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New post 23 May 2017, 01:03
rohit8865 wrote:
kimbercs wrote:
The area of square region S is what percent greater than the area of square region T?

1) The length of a side of square S is 10% greater than the length of a side of square T.

2) The length of a side of square S is 22 and the length of a side of square T is 20.

OA
D.



Let the side of 1st sq =x
then side of 2nd one is = 1.1x
thus thier respective area := x^2 and (1.1x)^2
let area of 2nd sq. be A % greater thus we can calculate as

(1.1x)^2 = x^2 (1+A/100)
so A can be calculated

suff

(2) let area of 2nd sq. be A % greater thus we can calculate as

(22)^2 = 20^2 (1+A/100)
so A can be calculated
(Note:- option 2 is similar to option 1 , as 22 is 10% greater than 20)
suff..

Ans D



It is not very clear how you derived on this part:

let area of 2nd sq. be A % greater thus we can calculate as

(1.1x)^2 = x^2 (1+A/100)
so A can be calculated

Kindly elaborate!
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Re: The area of square region S is what percent greater than [#permalink]

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New post 23 May 2017, 01:30
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michaelkalend wrote:
rohit8865 wrote:
kimbercs wrote:
The area of square region S is what percent greater than the area of square region T?

1) The length of a side of square S is 10% greater than the length of a side of square T.

2) The length of a side of square S is 22 and the length of a side of square T is 20.

OA
D.



Let the side of 1st sq =x
then side of 2nd one is = 1.1x
thus thier respective area := x^2 and (1.1x)^2
let area of 2nd sq. be A % greater thus we can calculate as

(1.1x)^2 = x^2 (1+A/100)
so A can be calculated

suff

(2) let area of 2nd sq. be A % greater thus we can calculate as

(22)^2 = 20^2 (1+A/100)
so A can be calculated
(Note:- option 2 is similar to option 1 , as 22 is 10% greater than 20)
suff..

Ans D



It is not very clear how you derived on this part:

let area of 2nd sq. be A % greater thus we can calculate as

(1.1x)^2 = x^2 (1+A/100)
so A can be calculated

Kindly elaborate!


If a number 'x' is A% greater than another number 'y', it means:
x = A% greater than y
x = y + A% of y
x = y + A/100 * y

Taking y common,
x = y (1 + A/100)
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Re: The area of square region S is what percent greater than [#permalink]

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New post 29 Jul 2017, 21:32
we can take values for the sides of the square and check if the percentage remains constant throughout. Therefore statement 1 is sufficient. Statement 2 gives us the values so that's also sufficient. Answer is D
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The area of square region S is what percent greater than [#permalink]

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New post 05 Sep 2017, 18:00
kimbercs wrote:
The area of square region S is what percent greater than the area of square region T?

1) The length of a side of square S is 10% greater than the length of a side of square T.

2) The length of a side of square S is 22 and the length of a side of square T is 20.

OA
D.


So this is actually a bit trickier than a standard 500 question but that's okay because the directory is not always accurate

St 1

Actually, if you just use 2 simple examples and apply the formula

new-old/old

You will find that the percentage increase in the area of a 1 x 1 and 2 x 2 square is exactly the same

St 2

clearly yes because we can just calculate the area and compare

D
The area of square region S is what percent greater than   [#permalink] 05 Sep 2017, 18:00
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