Let Average of group A be A
Group B then will be A+10000
We need to find the difference in their total earnings :
1. The total people no. of people is 100 :
Ax+Bx=100
So total earning of group A is A*Ax
and for B is it (A+10,000)*100-Ax
difference will be (A+10000)*(100-Ax)-A*Ax
100A+1000000-A*Ax-Ax*10000-A*Ax not sufficient to find the difference (NS)
Option 2:
Average of group A is 40000
Group B then will be 50000
But we don't know anything about the number of people in this groups , So not Sufficient alone (NS)
Now both together ,
Lets use the equation we had derived in option 1:
100A+1000000-A*Ax-Ax(10000)-A*Ax
Now we know the value of A as 40000 but still we can't say anything about Ax so it is not sufficient to find out the absolute value. Hence IMO option E
Bunuel
The average (arithmetic mean) earnings of the members of group A is $10,000 less than the average earnings of the members of group B. What is the difference in the total earnings between group A and group B?
(1) The total number of people in both groups is 100.
(2) The average earnings of the first group is $40,000
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