tannumunu wrote:
What if the other 2 numbers are 109 and 71 or 100 and 80? It is no where mentioned that the 2nd number has to be immediate smaller number than 120. So how we can eliminate 109/100? Please explain.
Hello Tannu,
We need to find the
smallest number out of the 3 and we are given that largest number is 120.
We also know that we have 3 different positive integers, i.e, the remaining 2 numbers are not equal.
Consider a parallel example: x + y = 5. (where x and y are positive integers)
If we want to find the
smallest out of x and y, the OTHER number HAS TO BE AS LARGE AS POSSIBLE, that is 4.
Why?
Consider y = 3:
x+3=5. Therefore x = 2. But is this the smallest POSSIBLE value that 'x' can take? 'x' will be as small as possible only when y will be as large as possible. In this case, if we take x + 4 = 5, then x will be equal to 1 (this can be the smallest possible positive integer. Therefore y has to be 4 (or
2nd number immediately smaller to 5, as you have pointed out).
With this understanding, you can re-read the solutions provided above and hopefully understand it better.
Hope this helped.
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