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Bunuel
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Average of 5,25,45 = 25
25-10 = 15 = Avg(10+30+x)
Hence x = 5 Option A
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Alternate approach
Let the number be x

Notice 10 and 35 (from set 2) are both 5 more than 5 and 25 (from set 1). Despite this, their avg is less than set 1

x-10-30 = 45 (x nullifies the extra 10 from other 2 numbers in the set and is still 30 short, given the avg is less than 10 for the 3 numbers, so the sum is 30 less)

x = 45 - 40 = 5
Bunuel
The average (arithmetic mean) of 5, 25, and 45 is 10 more than the average of 10, 30, and

(A) 5
(B) 15
(C) 25
(D) 35
(E) 45


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