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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
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The average (arithmetic mean) of 6 numbers is 8.5. When one number is discarded, the average of the remaining numbers becomes 7.2 .What is the discarded number?


Sol: Since avg is given for 6 nos, we can find the sum total which is 8.5*6= 51

New average after removal of one number is 7.2 so sum total of 5 nos is 36

Discarded number is 51-36=15

Ans E

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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
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Given that the average of 6 numbers is 8.5, then the sum of these numbers is 6*8.5= 51.

Let 'x' be the number removed, (51-x)/5 = 7.2. Solving for x, we get x = 15, so (E).
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
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Let's assume every number was 8.5 in the original set, now in order to reduce average to 7.2 by removing just one number, 1.3 \((8.5-7.2=1.3)\) needs to be subtracted from remaining 5 numbers \((1.3*5=6.5)\) along with removing one of the original numbers, i.e. \(6.5+8.5=15.0\)
Answer: E
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
Here is my solution to this one-->

Sum(1)=6*8.5=>51
Sum(2)=5*7.2=>36
Hence the discarded number must be 51-36=15

Hence E
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
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Bunuel
The average (arithmetic mean) of 6 numbers is 8.5. When one number is discarded, the average of the remaining numbers becomes 7.2. What is the discarded number?

(A) 7.8
(B) 9.8
(C) 10.0
(D) 12.4
(E) 15.0

\(8.5*6 - x = 7.2*5\)

Or, \(51 - x = 36\)

Or, \(x = 15\)

Hence, answer will be (E) 15
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
this can be solved very easily from the following method
N-7.2/6 +7.2=8.5 so the new no. will be after solving for N=15
so the answer is E
after knowing the S.D. very precisely we gonna solve these questions within 30 sec.
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
Bunuel
The average (arithmetic mean) of 6 numbers is 8.5. When one number is discarded, the average of the remaining numbers becomes 7.2. What is the discarded number?

(A) 7.8
(B) 9.8
(C) 10.0
(D) 12.4
(E) 15.0

\(8.5*6 - X = 7.2*5\)

\(51 - x = 36\)

Or, \(x = 15\)

Thus, the discarded number will be (E) 15.00
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
Quote:

The average (arithmetic mean) of 6 numbers is 8.5. When one number is discarded, the average of the remaining numbers becomes 7.2. What is the discarded number?

(A) 7.8
(B) 9.8
(C) 10.0
(D) 12.4
(E) 15.0

(8.5*6)-(7.2*5)=51-36=15. Option E.
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
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8.5*6= 51

7.2*5= 36

51-36=15

Answer is E.
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
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Theory

    ➡ Average = Sum of all the Values / Total Number of Values
    ➡ Sum of all the Values = Average * Total Number of Values

The average (arithmetic mean) of 6 numbers is 8.5

Sum of 6 numbers = Average * 6 = 8.5 * 6 = 51

When one number is discarded, the average of the remaining numbers becomes 7.2

Sum of remaining 5 numbers = Average * 5 = 7.2 * 5 = 36

Discarded number = Sum of 6 numbers - Sum of remaining 5 numbers = 51 - 36 = 15

So, Answer will be E.
Hope it helps!

Watch the following video to Learn the Basics of Statistics

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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
Let's denote the discarded number as x.

The average of 6 numbers is given as 8.5, so the sum of these 6 numbers is 6 * 8.5 = 51.

When the number x is discarded, the average of the remaining 5 numbers becomes 7.2. So, the sum of the remaining 5 numbers is 5 * 7.2 = 36.

To find the discarded number x, we can subtract the sum of the remaining 5 numbers from the sum of the original 6 numbers:

51 - 36 = 15

Therefore, the discarded number is 15.
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one [#permalink]
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