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The average (arithmetic mean) of 7, 5, 28, x, 4x, and y is x. 30 May 2021, 21:00
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Value
of x: 81 Value
of y: 41
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The average (arithmetic mean) of 7, 5, 28, x, 4x, and y is x.

In the table below, select two numbers that are consistent with the information that is given. In the first column, select the row that shows the value of x, and in the second column, select the row that shows the value of y. Make exactly one selection for each column.
Value
of x 		Value
of y
27
41
43
70
73
81
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Value
of x: 81 Value
of y: 41
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The average (arithmetic mean) of 7, 5, 28, x, 4x, and y is x. 30 May 2021, 21:47
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Y = 41.
X = 81

5 + 7 + 28 + x + 4x + y = 6x
40 + 5x + y = 6x
40 + y = x
40 + 41 = 81

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The average (arithmetic mean) of 7, 5, 28, x, 4x, and y is x. 08 Dec 2021, 00:24
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AS per the question, we need to calculate the Average of the given numbers. So,

(7 + 5 + 28 + x + 4x + y ) / 6 = x

Simplifying, we get 40 + y = x

Examine the values of x and y. We see that only when y = 41, we get another element - 81 - which is present in the given list.

SO, y = 41 and x = 81.
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The average (arithmetic mean) of 7, 5, 28, x, 4x, and y is x. 28 Jun 2024, 07:22
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