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Math Expert V
Joined: 02 Sep 2009
Posts: 58432
The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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Question Stats: 79% (01:49) correct 21% (02:35) wrong based on 20 sessions

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The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

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The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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Bunuel wrote:
The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

CONCEPT: Average consecutive integers = Median of consecutive Integers

i.e. _ _ _ _ _ _ _ 88 _ _ _ _ _ _ _

i.e. Greatest of them can be obtained by simply writing next consecutive terms

i.e. _ _ _ _ _ _ _ 88 89 90 91 92 93 94 95

ALTERNATIVE:

Let, smallest number = a

i.e. Largest number = a+14

Mean = a+7 = 88

i.e. a = 81

i.e. a+14 = 95

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Re: The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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The average mean of 15 consecutive integer is the 8th integer. The greatest of these integers would be the 15th. Thus 88+7=95

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Re: The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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Bunuel wrote:
The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

8th integer = 88

We need to find out 15th integer.

15 - 8 = 7.

So, 88 + 7 = 95

C is the correct answer.
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Re: The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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Bunuel wrote:
The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

a+7= 88
a= 81
a+14 ; 81+14 = 95
IMO C Re: The average (arithmetic mean) of fifteen consecutive integers is 88.   [#permalink] 01 Feb 2019, 11:36
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The average (arithmetic mean) of fifteen consecutive integers is 88.

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