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# The average (arithmetic mean) of fifteen consecutive integers is 88.

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Joined: 02 Sep 2009
Posts: 53020
The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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31 Jan 2019, 22:58
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Difficulty:

35% (medium)

Question Stats:

78% (01:50) correct 22% (01:44) wrong based on 10 sessions

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The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

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The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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31 Jan 2019, 23:05
Bunuel wrote:
The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

CONCEPT: Average consecutive integers = Median of consecutive Integers

i.e. _ _ _ _ _ _ _ 88 _ _ _ _ _ _ _

i.e. Greatest of them can be obtained by simply writing next consecutive terms

i.e. _ _ _ _ _ _ _ 88 89 90 91 92 93 94 95

ALTERNATIVE:

Let, smallest number = a

i.e. Largest number = a+14

Mean = a+7 = 88

i.e. a = 81

i.e. a+14 = 95

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Re: The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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31 Jan 2019, 23:07
The average mean of 15 consecutive integer is the 8th integer. The greatest of these integers would be the 15th. Thus 88+7=95

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Re: The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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01 Feb 2019, 09:27
Bunuel wrote:
The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

8th integer = 88

We need to find out 15th integer.

15 - 8 = 7.

So, 88 + 7 = 95

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Re: The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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01 Feb 2019, 10:36
Bunuel wrote:
The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

a+7= 88
a= 81
a+14 ; 81+14 = 95
IMO C
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Re: The average (arithmetic mean) of fifteen consecutive integers is 88.   [#permalink] 01 Feb 2019, 10:36
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