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03 Jul 2018, 00:18
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (00:50) correct
12%
(01:09)
wrong
based on 59
sessions
History
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Not Attempted Yet
The average (arithmetic mean) of five numbers is 25. After one of the numbers is removed, the average (arithmetic mean) of the remaining numbers is 31. What number has been removed?
(A) 1
(B) 6
(C) 11
(D) 24
(E) It cannot be determined from the information given.
(A) 1
(B) 6
(C) 11
(D) 24
(E) It cannot be determined from the information given.
03 Jul 2018, 00:33
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Bunuel
We'll translate our question into equations so we understand what we need to do.
This is a Precise approach.
If we treat the sum of the 4 remaining elements as one variable, S, and the 5th variable as x, then:
S/4 = 31 --> S = 124
(S+x)/5 = 25 --> 124 + x = 125
x = 1
(A) is our answer.
03 Jul 2018, 02:22
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[quote="Bunuel"]The average (arithmetic mean) of five numbers is 25. After one of the numbers is removed, the average (arithmetic mean) of the remaining numbers is 31. What number has been removed?
(A) 1
(B) 6
(C) 11
(D) 24
(E) It cannot be determined from the information given.[/quote
Sum of the 5 numbers = 5*25 = 125
Sum of the 4 numbers = 4 * 31 = 124
So the number that is removed = 125 - 124 = 1
The best answer is A.
(A) 1
(B) 6
(C) 11
(D) 24
(E) It cannot be determined from the information given.[/quote
Sum of the 5 numbers = 5*25 = 125
Sum of the 4 numbers = 4 * 31 = 124
So the number that is removed = 125 - 124 = 1
The best answer is A.
