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The average (arithmetic mean) of six numbers is 24. If the sum of four

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Bunuel
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The average (arithmetic mean) of six numbers is 24. If the sum of four [#permalink] New post   31 Jul 2019, 09:35
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The average (arithmetic mean) of six numbers is 24. If the sum of four of these numbers is 96, what is the average of the other 2 numbers?

A. 12
B. 24
C. 48
D. 72
E. 96
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Re: The average (arithmetic mean) of six numbers is 24. If the sum of four [#permalink] New post   31 Jul 2019, 09:42
arithmetic mean of 6 numbers is 24. This means that sum of these 6 no.s is 144 . we are given that sum of 4 no.s is 96, hence the sumo other 2 numbers is 144-96= 48 and their avg is 24
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The average (arithmetic mean) of six numbers is 24. If the sum of four [#permalink] New post   31 Jul 2019, 11:08
Bunuel wrote:
The average (arithmetic mean) of six numbers is 24. If the sum of four of these numbers is 96, what is the average of the other 2 numbers?

A. 12
B. 24
C. 48
D. 72
E. 96


Given: The average (arithmetic mean) of six numbers is 24. The sum of four of these numbers is 96.

Asked: What is the average of the other 2 numbers?


\(x_1+x_2+x_3+x_4+x_5+x_6=24*6=144\)

\(x_1+x_2+x_3+x_4=96\)

\(x_5+x_6= 144-96 = 48\)

Average of other 2 numbers = \(\frac{x_5+x_6}{2} = 24\)

IMO B
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Re: The average (arithmetic mean) of six numbers is 24. If the sum of four [#permalink] New post   05 Aug 2019, 17:24
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Bunuel wrote:
The average (arithmetic mean) of six numbers is 24. If the sum of four of these numbers is 96, what is the average of the other 2 numbers?

A. 12
B. 24
C. 48
D. 72
E. 96


The sum of the six numbers is 24 x 6 = 144, so the sum of the remaining two numbers is 144 - 96 = 48. Thus, the average of these two numbers is 48/2 = 24.

Answer: B
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Re: The average (arithmetic mean) of six numbers is 24. If the sum of four [#permalink] New post   26 Sep 2023, 07:59
Bunuel wrote:
The average (arithmetic mean) of six numbers is 24. If the sum of four of these numbers is 96, what is the average of the other 2 numbers?

A. 12
B. 24
C. 48
D. 72
E. 96

\(Σ_6 = 24*6 = 144\)
\(Σ_4 = 96\)

Thus, \(Σ_2 = Σ_6 - Σ_4\)

Or, \(Σ_2 = 144 - 96 = 48\)

Hence, Avg of \(2\) Nos will be \(\frac{48}{2} = 24\), Answer must be (B)
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Re: The average (arithmetic mean) of six numbers is 24. If the sum of four [#permalink]
26 Sep 2023, 07:59
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