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Bunuel
The average marks of 3/7th of the entire class is 70% of the average marks of the entire class. What is the ratio of the average marks of the remaining students of class to that of the entire class?

A. 49:40
B. 38:35
C. 25:21
D. 15:11
E. 7:5

­
Let n denote the number of students

Let a denote the average for the entire students.

Average = Sum/ number of elements

Then, sum = n*a

Given, 3/7th of students = (3/7) *n has generated an average of 70%*a

Inference: remaining students = n - (3/7)*n = (4/7)*n

Total sum generated by 3/7 th of student = (3/7)*n * [(70/100)*a] = (21 na)/70

Remaining sum equals = na - (21 na)/70 = (49* na )/70

Let the average of remaining students be B

(4/7)*n * B = (49* na )/70

on solving , we get

B = 49a/40


ratio of average of remaining students to average of entire students = ?

= (49a/40) : a

= 49/40

Option A
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