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The average of 20 numbers is zero. Of them, at the most, how many may

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The average of 20 numbers is zero. Of them, at the most, how many may  [#permalink]

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New post 21 Feb 2019, 00:10
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A
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C
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E

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  25% (medium)

Question Stats:

59% (00:42) correct 41% (00:52) wrong based on 22 sessions

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The average of 20 numbers is zero. Of them, at the most, how many may  [#permalink]

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New post Updated on: 21 Feb 2019, 12:51
[quote="Bunuel"]The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?

A. 0
B. 1
C. 10
D. 19
E. 18[/quote]

so total 20 no.s the avg = 0 means sum = 0
and the equal -ve and +ve integers
which would be possible -10 to 10 range only
so max +10 is possible in case of consective no .
But here it can be sum of 1-19 integers and -ve value of its sum so avg 0
IMO D
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Originally posted by Archit3110 on 21 Feb 2019, 08:41.
Last edited by Archit3110 on 21 Feb 2019, 12:51, edited 1 time in total.
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Re: The average of 20 numbers is zero. Of them, at the most, how many may  [#permalink]

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New post 21 Feb 2019, 09:02
total 20 no.s the avg = 0 means sum = 0
Its not mentioned in the question that number are in continuation. Hence, maximum 19 number can be +ve.

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Re: The average of 20 numbers is zero. Of them, at the most, how many may  [#permalink]

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New post 21 Feb 2019, 09:07
mohitranjan05 wrote:
total 20 no.s the avg = 0 means sum = 0
Its not mentioned in the question that number are in continuation. Hence, maximum 19 number can be +ve.

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mohitranjan05
what will be range according to you?
its given that total 20 nos are there and for sum to be = 0 ; it would be only possible when we have equal integers of both signs isnt it?
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Re: The average of 20 numbers is zero. Of them, at the most, how many may  [#permalink]

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New post 21 Feb 2019, 09:21
mohitranjan05 wrote:
total 20 no.s the avg = 0 means sum = 0
Its not mentioned in the question that number are in continuation. Hence, maximum 19 number can be +ve.

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assume that the sum of 19 positives = 19

then the next number = -19 is needed to make it zero .

so we may have 19 positives numbers whose sum will be equal to the last negative number to make the overall sum zero and henxe the average
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Re: The average of 20 numbers is zero. Of them, at the most, how many may  [#permalink]

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New post 24 Feb 2019, 06:47
Bunuel wrote:
The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?

A. 0
B. 1
C. 10
D. 19
E. 18


If the average of 20 numbers is zero, 19 of the numbers could be greater than zero and the last number could be less than zero (and it is the opposite of the sum of the other 19 numbers).

Answer: D
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Re: The average of 20 numbers is zero. Of them, at the most, how many may   [#permalink] 24 Feb 2019, 06:47
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