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09 Feb 2007, 12:00
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1. The average weight of 5 crates is 250 pounds. The 2 lightest crates weigh between 200 and 205 pounds each, and the 2 heaviest weigh between 300 and 310 pounds each. If the weight of the fifth crate is x pounds, then x is expressed by which of the following?
A. 220 <= x <= 250
B. 230 <= x <= 260
C 240 <= x <= 270
D. 250 <= x <= 270
E. 260 <= x <= 280
2.Mixture A is 15 percent alcohol, and mixture B is 50 percent alcohol. If the two are poured together to create a 4-gallon mixture that contains 30 percent alcohol, approximately how many gallons of mixture A are in the mixture?
A. 1.5
B. 1.7
C. 2.3
D. 2.5
E. 3.0
A. 220 <= x <= 250
B. 230 <= x <= 260
C 240 <= x <= 270
D. 250 <= x <= 270
E. 260 <= x <= 280
2.Mixture A is 15 percent alcohol, and mixture B is 50 percent alcohol. If the two are poured together to create a 4-gallon mixture that contains 30 percent alcohol, approximately how many gallons of mixture A are in the mixture?
A. 1.5
B. 1.7
C. 2.3
D. 2.5
E. 3.0
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09 Feb 2007, 12:30
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1) question
The average weigth of 5 crates is 250. so the sum of the weigths is 1250
2 ligther crates weigth 200-205, so the sum of the weigths must be between 400-410
2 heviest weigth 300-310 so the sum is 600-620
Total weigth = 1250
The weight of the remaining crate must be between:
400+600=1000; 410+620=1030
1250-1000=250 and 1250-1030=220
x must be between 220 and 250
A
The average weigth of 5 crates is 250. so the sum of the weigths is 1250
2 ligther crates weigth 200-205, so the sum of the weigths must be between 400-410
2 heviest weigth 300-310 so the sum is 600-620
Total weigth = 1250
The weight of the remaining crate must be between:
400+600=1000; 410+620=1030
1250-1000=250 and 1250-1030=220
x must be between 220 and 250
A
09 Feb 2007, 12:51
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2) question
I would suggest to construct a table on mixture problems:
You have to find X
A: 0.15x of alcohol 0.85x of other stuff TOTAL x
B: 0.5y of alcohol 0.5y of other stuff TOTAL y
A+B: 1.2 liters of alcohol 2.8 liters of other stuff TOTAL 4 liters
Now you simply construct the equation:
one equation: 0.15x+0.5y=1.2......multiply by -2
second eqation: x+y=4
-0.3x-y=-2.4
x+y=4
Add both together
0.7x=1.6
x=2.3 approximately....
C
I would suggest to construct a table on mixture problems:
You have to find X
A: 0.15x of alcohol 0.85x of other stuff TOTAL x
B: 0.5y of alcohol 0.5y of other stuff TOTAL y
A+B: 1.2 liters of alcohol 2.8 liters of other stuff TOTAL 4 liters
Now you simply construct the equation:
one equation: 0.15x+0.5y=1.2......multiply by -2
second eqation: x+y=4
-0.3x-y=-2.4
x+y=4
Add both together
0.7x=1.6
x=2.3 approximately....
C
