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19 May 2022, 09:00
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The average weight of 6 persons increases by 3.5 kg when a new person comes in place of one of them weighing 59 kg. What might be the weight of the new person ?
(A) 76 kg
(B) 80 kg
(C) 85 kg
(D) 86 kg
(E) 87 kg
(A) 76 kg
(B) 80 kg
(C) 85 kg
(D) 86 kg
(E) 87 kg
genericUser
Joined: 31 Jan 2022
Last visit: 22 Dec 2023
Posts: 111
Own Kudos:
Given Kudos: 35
Location: Italy
Schools: SDA Bocconi "24 (M)
GMAT 1: 670 Q49 V33
GMAT 2: 690 Q47 V37
GPA: 3.9
19 May 2022, 09:15
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The average weight of 6 persons increases by 3.5 kg when a new person comes in place of one of them weighing 59 kg. What might be the weight of the new person ?
(A) 76 kg
(B) 80 kg
(C) 85 kg
(D) 86 kg
(E) 87 kg
let \(o=59\) be the old person
let \(n\) be the new person
let \(x\) be the sum of the weight of the 5 persons who remain the same
equate the avg
\(3.5+\frac{x+o}{6}=\frac{x+n}{6}\)
\(6*(3.5+\frac{x+o}{6})=6*(\frac{x+n}{6})\)
\(21+x+o=x+n\)
\(21+o=n\)
\(21+59=n\)
\(n=80\)
(A) 76 kg
(B) 80 kg
(C) 85 kg
(D) 86 kg
(E) 87 kg
let \(o=59\) be the old person
let \(n\) be the new person
let \(x\) be the sum of the weight of the 5 persons who remain the same
equate the avg
\(3.5+\frac{x+o}{6}=\frac{x+n}{6}\)
\(6*(3.5+\frac{x+o}{6})=6*(\frac{x+n}{6})\)
\(21+x+o=x+n\)
\(21+o=n\)
\(21+59=n\)
\(n=80\)
19 May 2022, 09:23
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(x-59)/6=3.5
=> x= 80
Posted from my mobile device
=> x= 80
Posted from my mobile device
