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Bunuel

Tough and Tricky questions: Word Problems.




The chart above shows the distribution of letter grades for three groups of students on one test. Point values are assigned to the letter grades so that A = 4 points, B = 3 points, C = 2 points, and D = 1 point. Which of the following values is closest to the average (arithmetic mean) grade of students in group 3?

A. 2.2
B. 2.4
C. 2.9
D. 3.1
E. 3.7

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Attachment:
2015-01-05_1753.png

total of group 3 = 4*1 + 7*2 + 9*3 + 2*4 = 53
Total students 22

Mean = 53/22 = 2.4
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Answer = B. 2.4

Attachment:
2015-01-05_1753.png
2015-01-05_1753.png [ 5.71 KiB | Viewed 11541 times ]

Mean of Group 3 \(= \frac{4*1 + 7*2 + 9*3 + 2*4}{4+7+9+2} = \frac{53}{22} = 2.4\)
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Bunuel

Tough and Tricky questions: Word Problems.




The chart above shows the distribution of letter grades for three groups of students on one test. Point values are assigned to the letter grades so that A = 4 points, B = 3 points, C = 2 points, and D = 1 point. Which of the following values is closest to the average (arithmetic mean) grade of students in group 3?

A. 2.2
B. 2.4
C. 2.9
D. 3.1
E. 3.7

Kudos for a correct solution.

Attachment:
2015-01-05_1753.png

OFFICIAL SOLUTION:

(B) There are 4 + 7 + 9 + 2 = 22 students in group 3.

The grade distribution in group 3 was:
4 students received a grade of D.
7 students received a grade of C.9 students received a grade of B.
2 students received a grade of A.

Therefore, the sum of the grade points for group 3 is:
(4 × 1) + (7 × 2) + (9 × 3) + (2 × 4) =
4 + 14 + 27 + 8 = 53.

We can find the average grade in group 3 by dividing this sum by the number of students in group 3:
Average for group 3 = 53/22.

Performing the required division, we see that 2.4 is the closest answer choice.

The correct answer is choice (B).
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