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03 Jul 2019, 23:39
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
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Question Stats:
95% (01:40) correct
5%
(01:29)
wrong
based on 59
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The distance between Town X and Town Y is twice the distance between Town X and Town Z. The distance between Town Z and Town W is 2/3 the distance between Town Z and Town X. If the distance between Town Z and Town W is 18 miles, how far is Town X from Town Y?
A. 26
B. 27
C. 52
D. 53
E. 54
A. 26
B. 27
C. 52
D. 53
E. 54
Archit3110
04 Jul 2019, 03:33
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Bunuel
distan xy = 2*d xz
and d zw=2/3 d zx
given d zw=18
so d zx= 27
and d xy= 54
IMO E
04 Jul 2019, 03:34
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Let us represent the respective distances using the names of the towns.
Let distance between town X and town Y = XY; distance between town X and town Z = XZ, distance between town Z and town W = WZ.
Let us now connect these unknowns using equations.
XY = 2 XZ, which can be equation 1.
WZ = \(\frac{2}{3}\) XZ, which can be equation 2.
The question says that WZ = 18. Substituting this in equation 2,
18 = \(\frac{2}{3}\)XZ which yields us XZ = 27. Substituting this in equation 1, we have,
XY = 2*27 = 54.
Therefore, town X is 54 km away from town Y. The correct answer option is E.
Hope this helps!
Let distance between town X and town Y = XY; distance between town X and town Z = XZ, distance between town Z and town W = WZ.
Let us now connect these unknowns using equations.
XY = 2 XZ, which can be equation 1.
WZ = \(\frac{2}{3}\) XZ, which can be equation 2.
The question says that WZ = 18. Substituting this in equation 2,
18 = \(\frac{2}{3}\)XZ which yields us XZ = 27. Substituting this in equation 1, we have,
XY = 2*27 = 54.
Therefore, town X is 54 km away from town Y. The correct answer option is E.
Hope this helps!
