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03 Apr 2020, 06:01
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C
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Difficulty:
65%
(hard)
Question Stats:
67% (03:02) correct
33%
(03:08)
wrong
based on 268
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The distance from A to B is 60 km. Partha and Narayan start from A at the same time and move towards B. Partha takes four hours more than Narayan to reach B. Moreover, Partha reaches the mid-point of A and B two hours before Narayan reaches B. What is the speed of Partha, in km per hour?
A. 7
B. 6
C. 5
D. 4
E. 3
Are You Up For the Challenge: 700 Level Questions
A. 7
B. 6
C. 5
D. 4
E. 3
Are You Up For the Challenge: 700 Level Questions
03 Apr 2020, 07:05
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Bunuel
Partha takes four hours more than Narayan to reach B
Let the time taken by Partha = \(t\) & that of Narayan = \(t - 4\)
--> Speed of Partha, \(s_p = \frac{60}{t}\) & Speed of Narayan, \(s_n = \frac{60}{t - 4}\)
Partha reaches the mid-point of A and B two hours before Narayan reaches B
--> \(\frac{60}{s_n} - \frac{30}{s_p} = 2\)
--> \(\frac{2}{s_n} - \frac{1}{s_p} = \frac{1}{15}\)
--> \(\frac{2(t - 4)}{60} - \frac{t}{60} = \frac{1}{15}\)
--> \(2t - 8 - t = 4\)
--> \(t = 12\) hours
--> Speed of Partha, \(s_p = \frac{60}{t} = \frac{60}{12} = 5\) kmph
Option C
04 Apr 2020, 08:58
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let time taken by Narayan to reach B = t hour
So time taken by Partha to reach B = (t+4) hours
Time taken by Partha to reach mid point of A and B = (t+ 4)/2
Given t – (t+ 4)/2 = 2
2t – t – 4 = 4
t = 8 hours
Speed of Partha = 60/(t+4) = 60/12 = 5 km/hour
Correct option C
So time taken by Partha to reach B = (t+4) hours
Time taken by Partha to reach mid point of A and B = (t+ 4)/2
Given t – (t+ 4)/2 = 2
2t – t – 4 = 4
t = 8 hours
Speed of Partha = 60/(t+4) = 60/12 = 5 km/hour
Correct option C
