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# The figure above is a square. What is its area?

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Math Expert
Joined: 02 Sep 2009
Posts: 42249

Kudos [?]: 132619 [0], given: 12326

The figure above is a square. What is its area? [#permalink]

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26 Sep 2017, 23:26
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(N/A)

Question Stats:

85% (00:14) correct 15% (00:05) wrong based on 20 sessions

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The figure above is a square. What is its area?

(A) 9
(B) 4
(C) 1
(D) 1/4
(E) cannot be determined

[Reveal] Spoiler:
Attachment:

2017-09-27_1016.png [ 1.99 KiB | Viewed 343 times ]
[Reveal] Spoiler: OA

_________________

Kudos [?]: 132619 [0], given: 12326

Director
Joined: 25 Feb 2013
Posts: 542

Kudos [?]: 246 [0], given: 33

Location: India
Schools: Mannheim"19 (S)
GPA: 3.82
Re: The figure above is a square. What is its area? [#permalink]

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26 Sep 2017, 23:54
Bunuel wrote:

The figure above is a square. What is its area?

(A) 9
(B) 4
(C) 1
(D) 1/4
(E) cannot be determined

[Reveal] Spoiler:
Attachment:
2017-09-27_1016.png

as it is a square $$3x-1=x$$

or $$x=\frac{1}{2}$$

Hence area $$= x^2 =\frac{1}{4}$$

Option D

Kudos [?]: 246 [0], given: 33

Manager
Joined: 06 Aug 2017
Posts: 72

Kudos [?]: 13 [0], given: 27

GMAT 1: 610 Q48 V24
Re: The figure above is a square. What is its area? [#permalink]

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26 Sep 2017, 23:55
Bunuel wrote:

The figure above is a square. What is its area?

(A) 9
(B) 4
(C) 1
(D) 1/4
(E) cannot be determined

[Reveal] Spoiler:
Attachment:
2017-09-27_1016.png

The answer should be D as follows.

The two sides given are x and 3x-1.
since the figure is a squire, both the sides should be equal in length ==> x=3x-1 ==>2x=1 ==>$$x=\frac{1}{2}$$
Area of the squire = $$side^2$$ ==> $$x^2$$ ==> $$(\frac{1}{2})^2$$ ==>$$\frac{1}{4}$$

Hence answer is D ($$\frac{1}{4}$$)
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Kudos [?]: 13 [0], given: 27

Re: The figure above is a square. What is its area?   [#permalink] 26 Sep 2017, 23:55
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