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The figure shows all the available routes between stations A and C

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The figure shows all the available routes between stations A and C [#permalink]

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New post Updated on: 15 Mar 2018, 23:22
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A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

61% (01:11) correct 39% (01:12) wrong based on 217 sessions

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The figure shows all the available routes between stations A and C. What is the shortest route available to reach station C from A ?

(1) AB < AE < AD
(2) BC < EC < CD




[Reveal] Spoiler: Solution:
Attachment:
File comment: this is the question
zig.png
zig.png [ 17.58 KiB | Viewed 2177 times ]


There is another route ABFC.

BF+FC can be greater than BC,
Or BF+FC can be smaller than BC.
Because we don’t know anything about BF .
So we have a double case and thus the answer is (E)
[Reveal] Spoiler: OA

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Originally posted by Asifpirlo on 04 Aug 2013, 14:29.
Last edited by Bunuel on 15 Mar 2018, 23:22, edited 2 times in total.
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Re: The figure shows all the available routes between stations A and C [#permalink]

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New post 04 Aug 2013, 15:26
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Thanks for posting this one.

I like not drawn to scale questions. Is this your own? It's pretty good.
You may want to hide the tips and the solution - I have the spoiler tag for that in this case. PM me if you have questions.
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Re: The figure shows all the available routes between stations A and C [#permalink]

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New post 04 Aug 2013, 15:56
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Asifpirlo wrote:
The figure shows all the available routes between stations A and C . what is the shortest route available to reach station C from A ?
(1) AB < AE < AD
(2) BC < EC < CD

WHAT IS YOUR ANSWER?
ABC is THE SHORTEST ROUTE
Then you are wrong.
:cry:


Attachment:
zig.png



[Reveal] Spoiler: Solution:
There is another route ABFC.

BF+FC can be greater than BC,
Or BF+FC can be smaller than BC.
Because we don’t know anything about BF .
So we have a double case and thus the answer is (E)


there are 5 paths available:
1) A=>B=>C
2) A=>B=>F=>C
3) A=>E=>F=>C
4) A=>E=>F=>B=>C
5) A=>D=>C

NOW we have to find out the shortest path.

stmnt 1: AB < AE < AD
insufficient as it is fragment of full distance.

stmnt2: BC < EC < CD
insufficient as it is fragment of full distance.

combining we can make out that
path 1 < path 3 < path 5
but we dont know about paths 2 and 4 as we dont that B=>F=>C is shorter/longer than B=>C

HENCE E
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Re: The figure shows all the available routes between stations A and C [#permalink]

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New post 15 Mar 2018, 23:18
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Re: The figure shows all the available routes between stations A and C   [#permalink] 15 Mar 2018, 23:18
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