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# The figure shows all the available routes between stations A and C

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Joined: 10 Jul 2013
Posts: 289
The figure shows all the available routes between stations A and C  [#permalink]

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Updated on: 15 Mar 2018, 23:22
1
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Difficulty:

65% (hard)

Question Stats:

56% (01:46) correct 44% (01:38) wrong based on 220 sessions

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The figure shows all the available routes between stations A and C. What is the shortest route available to reach station C from A ?

(1) AB < AE < AD
(2) BC < EC < CD

Spoiler: :: Solution:
Attachment:
File comment: this is the question

zig.png [ 17.58 KiB | Viewed 2398 times ]

There is another route ABFC.

BF+FC can be greater than BC,
Or BF+FC can be smaller than BC.
Because we don’t know anything about BF .
So we have a double case and thus the answer is (E)

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Asif vai.....

Originally posted by Asifpirlo on 04 Aug 2013, 14:29.
Last edited by Bunuel on 15 Mar 2018, 23:22, edited 2 times in total.
Hid the solution
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Re: The figure shows all the available routes between stations A and C  [#permalink]

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04 Aug 2013, 15:26
1
Thanks for posting this one.

I like not drawn to scale questions. Is this your own? It's pretty good.
You may want to hide the tips and the solution - I have the spoiler tag for that in this case. PM me if you have questions.
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Re: The figure shows all the available routes between stations A and C  [#permalink]

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04 Aug 2013, 15:56
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Asifpirlo wrote:
The figure shows all the available routes between stations A and C . what is the shortest route available to reach station C from A ?
(1) AB < AE < AD
(2) BC < EC < CD

ABC is THE SHORTEST ROUTE
Then you are wrong.

Attachment:
zig.png

Spoiler: :: Solution:
There is another route ABFC.

BF+FC can be greater than BC,
Or BF+FC can be smaller than BC.
Because we don’t know anything about BF .
So we have a double case and thus the answer is (E)

there are 5 paths available:
1) A=>B=>C
2) A=>B=>F=>C
3) A=>E=>F=>C
4) A=>E=>F=>B=>C
5) A=>D=>C

NOW we have to find out the shortest path.

stmnt 1: AB < AE < AD
insufficient as it is fragment of full distance.

stmnt2: BC < EC < CD
insufficient as it is fragment of full distance.

combining we can make out that
path 1 < path 3 < path 5
but we dont know about paths 2 and 4 as we dont that B=>F=>C is shorter/longer than B=>C

HENCE E
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Re: The figure shows all the available routes between stations A and C  [#permalink]

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15 Mar 2018, 23:18
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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: The figure shows all the available routes between stations A and C   [#permalink] 15 Mar 2018, 23:18
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# The figure shows all the available routes between stations A and C

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