PrakharGMAT wrote:

Hi

Bunuel /

chetan2u,

I am not able to understand, how can you say that the graph move up 2 units up. I can see that in second equation there is "+2" but still how could you say.

If the equation would have been y = (x + 1)(x - 1)^2 - 2. Then will the graph will move 2 stps down..??

If the equation would have been x = (y + 1)(y - 1)^2 and some graph was given and we need to find the intercept of equation x = (y + 1)(y - 1)^2 + 2 or x = (y + 1)(y - 1)^2 -2. Then how will the graph move.

I have gone through the link

math-coordinate-geometry-87652.html but it does not provide anything related to the movement of graph. Can you please provide basic understanding on the movement of graph so that if I come across any weired equation in exam I can make a rough idea of it.

I can't take this question lightly because its an official GMAT Prep question.

Please assist.

Thanks and Regards.

Prakhar

Hi,

let \(y = (x + 1)(x - 1)^2\)...

and \(y_1 = (x + 1)(x - 1)^2 +2 = y+2\)......

so when \(x= 0... y = (0+1)(0-1)^2 = 1\) and \(y_1 = (0+1)(0-1)^2 + 2 = 1+2 = 3\)

when \(x=1... y = (1+1)(1-1)^2 = 0\)and \(y_1=0+2 = 2\)..

so for earlier existing values of y, \(y_1\) is 2 more so the values of y has shifted two points up in new graph although the graph remains the same..

**Quote:**

If the equation would have been y = (x + 1)(x - 1)^2 - 2. Then will the graph will move 2 stps down..??

YES

\(x = (y + 1)(y - 1)^2\)and \(x_1 = (y + 1)(y - 1)^2 + 2\).... the graph will move two steps right

DRAW the graph for all four and you will strengthen the concept on this

Hope it is clear

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