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The financial aid office of a certain college has agreed to provide

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The financial aid office of a certain college has agreed to provide  [#permalink]

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New post 29 Sep 2018, 02:19
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The financial aid office of a certain college has agreed to provide a $9,000 grant to every student whose total family income (not including the grant) is $22,500 or less. However, for every $40 in family income above this figure, the grant is reduced by $10. If Cedric's award is reduced 40%, what is his family income?

A) $26,100
B) $27,000
C) $31,500
D) $36,900
E) $ 44,100

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Re: The financial aid office of a certain college has agreed to provide  [#permalink]

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New post 29 Sep 2018, 10:04
Cedric's award is reduced 40% = 9000*.4 = 3600
For every 40$ above , 10$ is reduced. Therefore , his family income was 22500 + (3600*40) = 36900
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Re: The financial aid office of a certain college has agreed to provide  [#permalink]

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New post 01 Oct 2018, 03:44
pandeyashwin wrote:
Cedric's award is reduced 40% = 9000*.4 = 3600
For every 40$ above , 10$ is reduced. Therefore , his family income was 22500 + (3600*40) = 36900


it should be 22500 + (3600*40/10) = 36900
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The financial aid office of a certain college has agreed to provide  [#permalink]

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New post 01 Oct 2018, 04:30
Harshgmat wrote:
The financial aid office of a certain college has agreed to provide a $9,000 grant to every student whose total family income (not including the grant) is $22,500 or less. However, for every $40 in family income above this figure, the grant is reduced by $10. If Cedric's award is reduced 40%, what is his family income?

A) $26,100
B) $27,000
C) $31,500
D) $36,900
E) $ 44,100


Cedric's award = \(60/100($9000) = $5,400\).

For every \($40\) higher than \($22,500\) the grant gets reduced by \($10\): here the grant got reduced by \($3,600\), i.e., \(3600/10 = 360\) times, by \($40\). So, the family income must be \($22,500 + (360*40) = $36,900\). Ans - D.
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The financial aid office of a certain college has agreed to provide   [#permalink] 01 Oct 2018, 04:30
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