Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
04 Dec 2020, 01:15
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
78% (02:36) correct
22%
(02:44)
wrong
based on 209
sessions
History
Date
Time
Result
Not Attempted Yet
The first three terms of an arithmetic progression are 3x - 5, 2x + 3, and 5x - 1, respectively. What is the 100th term of this sequence? (An arithmetic progression is a sequence of numbers such that the difference of any two successive members is a constant.)
A. 199
B. 299
C. 399
D. 499
E. 599
Are You Up For the Challenge: 700 Level Questions
A. 199
B. 299
C. 399
D. 499
E. 599
Are You Up For the Challenge: 700 Level Questions
04 Dec 2020, 03:11
Kudos
Bookmarks
Explanation:
In AP Difference between any 2 terms are always the same.
T2-T1 = T3-T2
(2x+3) - (3x-5) = (5x-1) - (2x+3)
-x + 8 = 3x - 4
12 = 4x
x = 3
So Terms are 4,9,14
Common difference is (9-4) = 5 , first term is 4
100th term = a + (n-1)d
= 4 + (100-1)x5
= 4 + 99x5
= 499
IMO-D
In AP Difference between any 2 terms are always the same.
T2-T1 = T3-T2
(2x+3) - (3x-5) = (5x-1) - (2x+3)
-x + 8 = 3x - 4
12 = 4x
x = 3
So Terms are 4,9,14
Common difference is (9-4) = 5 , first term is 4
100th term = a + (n-1)d
= 4 + (100-1)x5
= 4 + 99x5
= 499
IMO-D
04 Dec 2020, 07:13
Kudos
Bookmarks
Bunuel
AP: a, a+d, a+2d..
d = common difference
a = first term
2x+3-(3x-5)=5x-1-(2x+3)
2x+3-3x+5=5x-1-2x-3
-x+8=3x-4, 4x=12, x=3
a=3x-5=9-5=4
a+d=4+d=2x+3, 4+d=6+3, d=9-4=5
n=100: a+d(n-1)=4+5(99)=450+45+4=499
(D)
