The graph refers to a captive population of animals. For each month of

Question

https://s3.amazonaws.com/wmx-api-production/courses/61222/images/Screenshot%202024-02-01%20131217.png

The graph refers to a captive population of animals. For each month of a consecutive 11-month period, it depicts the number of animals that died and the number of animals that were born. These were the only population changes; no animals joined the population from outside, and no animals (except those that died and were removed) left the population.

Based on the information provided, select from each drop-down menu the option that creates the most accurate statement.

At the end of the 11-month period, the number of animals in the population was  GRAPH_1_PLACEHOLDER  the number of animals in the population at the beginning of the period.

The monthly totals of births and deaths resulted in a net population increase in  GRAPH_2_PLACEHOLDER  of the months.

Elite097 · Answer

KarishmaB   GMATinsight  solution pls

Anilkumart1612 · Answer

In the above graph,every month more animals are died than born.

Definitely number of animals are decreased.

Posted from my mobile device

rito54 · Answer

Hello anyone would have the solution of this problem? Thank you!

Harish_IITB · Answer

Let me answer this question.

1) At the end of the 11-month period, the number of animals in the population was  less than 
 the number of animals in the population at the beginning of the period.
 Reason: In all the months Died numbers were higher than born. So after 11 months total no. of animals will decrease.

2) The monthly totals of births and deaths resulted in a net population increase in  none  of the months.
 Reason: Because at no month born number was more than died. (Black line (born) was always less than blue (died))

Purnank · Answer

just look at the graph for every month death number is always greater than born number so this will lead to population decrease and in similar way for second line "none" as increase never happened at any given month.

pierjoejoe · Answer

consider the areas, like an integral. if the area under the curve and is greater, it means that the sum of each data point from the beginning to the end is greater. in this case the area of the "death" is greater than the area of "born", thus the sum of the baby born in the period is less than the sum of the death in the priod. thus we can conclude that the population shrinked in the period

siddhantvarma · Answer

1. Net population change over the 11 months
Compare the number of births and deaths each month to calculate the net change
Total net change = sum of all net changes = -60 -55 -20 -85 -35 -10 -5 + 0 + 0 -10 -5 = -285
=> The number of animals at the end was  less than  the number at the beginning.
 Had the net change been positive, we would have marked "greater than" here.

2. Months with net population increase (more births than deaths)
There is  no month  where the number of births exceeded the number of deaths. At best, the numbers were equal (months 8 and 9). => None of the months

The graph refers to a captive population of animals. For each month of

Prep Toolkit

Top 5 GMAT Debrief Videos

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards

GMAT Graphs and Tables (G&T) Questions

The graph refers to a captive population of animals. For each month of

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards