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LMP
Joined: 29 Jun 2018
Last visit: 15 Mar 2022
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Schools: Johnson '20 HEC Montreal '21
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09 Aug 2018, 03:15
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
88% (01:23) correct
13%
(01:03)
wrong
based on 8
sessions
History
Date
Time
Result
Not Attempted Yet
The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:
A. 3
B. 13
C. 23
D. 33
E . 37
A. 3
B. 13
C. 23
D. 33
E . 37
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09 Aug 2018, 03:28
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Bulusuchaitanya
Let x be added to 2497 so that the required condition is met.
Given (2497+x) is divisible by 5, 6, 4 and 3. So, it it is implied that (2497+x) is divisible by LCM(5,6,4,3) i.e, 60.
Now Rem(\(\frac{2497}{60}\))=37
So, x=60-37=23.
Ans. (C)
09 Aug 2018, 03:30
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Bulusuchaitanya
OA: C
Let x be the least number that needs to be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3
Sum of 2497 and x should be multiple of L.C.M of 5,6,4 and 3 i.e 60
2497+ x = 60n
60n can be 2400,2460,2520,2580.............
2520 is closest to 2497 and would give the least positive value of x
2497 +x =2520
x= 23
