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# the least number

Author Message
Intern
Joined: 29 Jun 2018
Posts: 15
Location: India
GMAT 1: 530 Q42 V26
GPA: 4

### Show Tags

09 Aug 2018, 02:15
00:00

Difficulty:

35% (medium)

Question Stats:

87% (00:51) correct 13% (00:31) wrong based on 15 sessions

### HideShow timer Statistics

The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:

A. 3
B. 13
C. 23
D. 33
E . 37
Director
Status: Learning stage
Joined: 01 Oct 2017
Posts: 931
WE: Supply Chain Management (Energy and Utilities)

### Show Tags

09 Aug 2018, 02:28
Bulusuchaitanya wrote:
The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:

A. 3
B. 13
C. 23
D. 33
E . 37

Let x be added to 2497 so that the required condition is met.

Given (2497+x) is divisible by 5, 6, 4 and 3. So, it it is implied that (2497+x) is divisible by LCM(5,6,4,3) i.e, 60.

Now Rem($$\frac{2497}{60}$$)=37

So, x=60-37=23.

Ans. (C)
_________________

Regards,

PKN

Rise above the storm, you will find the sunshine

Senior Manager
Joined: 18 Jun 2018
Posts: 252

### Show Tags

09 Aug 2018, 02:30
Bulusuchaitanya wrote:
The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:

A. 3
B. 13
C. 23
D. 33
E . 37

OA: C
Let x be the least number that needs to be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3
Sum of 2497 and x should be multiple of L.C.M of 5,6,4 and 3 i.e 60
2497+ x = 60n
60n can be 2400,2460,2520,2580.............
2520 is closest to 2497 and would give the least positive value of x
2497 +x =2520
x= 23
VP
Joined: 07 Dec 2014
Posts: 1128

### Show Tags

09 Aug 2018, 20:12
Bulusuchaitanya wrote:
The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:

A. 3
B. 13
C. 23
D. 33
E . 37

5,6,4 and 3 are all factors of 60
2497/60 leaves a remainder of 37
60-37=23
C
the least number &nbs [#permalink] 09 Aug 2018, 20:12
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