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  • Typical Day of a UCLA MBA Student - Recording of Webinar with UCLA Adcom and Student

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the least number

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Intern
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Joined: 29 Jun 2018
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the least number  [#permalink]

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New post 09 Aug 2018, 02:15
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A
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Difficulty:

  35% (medium)

Question Stats:

87% (00:51) correct 13% (00:31) wrong based on 15 sessions

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The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:

A. 3
B. 13
C. 23
D. 33
E . 37
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Re: the least number  [#permalink]

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New post 09 Aug 2018, 02:28
Bulusuchaitanya wrote:
The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:

A. 3
B. 13
C. 23
D. 33
E . 37


Let x be added to 2497 so that the required condition is met.

Given (2497+x) is divisible by 5, 6, 4 and 3. So, it it is implied that (2497+x) is divisible by LCM(5,6,4,3) i.e, 60.

Now Rem(\(\frac{2497}{60}\))=37

So, x=60-37=23.

Ans. (C)
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Re: the least number  [#permalink]

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New post 09 Aug 2018, 02:30
Bulusuchaitanya wrote:
The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:

A. 3
B. 13
C. 23
D. 33
E . 37


OA: C
Let x be the least number that needs to be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3
Sum of 2497 and x should be multiple of L.C.M of 5,6,4 and 3 i.e 60
2497+ x = 60n
60n can be 2400,2460,2520,2580.............
2520 is closest to 2497 and would give the least positive value of x
2497 +x =2520
x= 23
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the least number  [#permalink]

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New post 09 Aug 2018, 20:12
Bulusuchaitanya wrote:
The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:

A. 3
B. 13
C. 23
D. 33
E . 37


5,6,4 and 3 are all factors of 60
2497/60 leaves a remainder of 37
60-37=23
C
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the least number &nbs [#permalink] 09 Aug 2018, 20:12
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