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19 Sep 2017, 23:46
Kudos
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A
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Difficulty:
15%
(low)
Question Stats:
84% (01:31) correct
16%
(01:44)
wrong
based on 85
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The length of a rectangular field X is 2 kilometers greater than the side of square field Y, and the width of field X is 2 kilometers less than the side of field Y. If y^2 is the area of field Y in square kilometers, which of the following gives the area, in square kilometers, of field X?
(A) y^2 – 4
(B) y^2 – 2
(C) y^2
(D) y^2 + 2
(E) y^2 + 4
(A) y^2 – 4
(B) y^2 – 2
(C) y^2
(D) y^2 + 2
(E) y^2 + 4
20 Sep 2017, 11:03
Kudos
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Bunuel
Let s be the side of the square field and l,b be the length and width of the rectangular field respectively.
l=s+2
b=s-2
Area of field X = lxb = (s+2)(s-2)=s^2-4
Area of field Y = y^2
Hence, y^2=s^2 (area of square = side^2)
Therefore, Area of field X =y^2-4
Answer A.
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