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The length of rectangular box is increased by 20 percent while its wid

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The length of rectangular box is increased by 20 percent while its wid  [#permalink]

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New post 25 Jul 2018, 23:07
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The length of rectangular box is increased by 20 percent while its width is decreased by 20 percent. The volume of the altered rectangular box is what percent of the volume of the original rectangular box?

A. 60%
B. 96%
C. 100%
D. 140%
E. 144%

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Re: The length of rectangular box is increased by 20 percent while its wid  [#permalink]

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New post 26 Jul 2018, 00:10
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Bunuel wrote:
The length of rectangular box is increased by 20 percent while its width is decreased by 20 percent. The volume of the altered rectangular box is what percent of the volume of the original rectangular box?

A. 60%
B. 96%
C. 100%
D. 140%
E. 144%


Original volume = L*B*H
Altered volume = 1.20*0.80*L*B*H

Now,
= (Altered volume / Original Volume) * 100
= (1.20*0.80*L*B*H / L*B*H) * 100
= (0.96*L*B*H / L*B*H) * 100
= 96 %

Hence, B.
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Re: The length of rectangular box is increased by 20 percent while its wid  [#permalink]

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New post 26 Jul 2018, 00:38
Bunuel wrote:
The length of rectangular box is increased by 20 percent while its width is decreased by 20 percent. The volume of the altered rectangular box is what percent of the volume of the original rectangular box?

A. 60%
B. 96%
C. 100%
D. 140%
E. 144%



Original Rectangle :

length = 100

width = 100

Area - 100 *100 = 1000

Altered rectangle :

length = 120

width = 80

Area = 960

Required % = (960 /1000) * 100 = 96%


The best answer is B.
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Re: The length of rectangular box is increased by 20 percent while its wid  [#permalink]

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New post 30 Jul 2018, 10:45
Bunuel wrote:
The length of rectangular box is increased by 20 percent while its width is decreased by 20 percent. The volume of the altered rectangular box is what percent of the volume of the original rectangular box?

A. 60%
B. 96%
C. 100%
D. 140%
E. 144%



The original volume is LWH.

The new volume is L x 1.2 x W x 0.8 x H = 0.96LWH

So the volume of the altered box is 0.96LWH/LWH = 96% of the volume of the original box.

Answer: B
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Re: The length of rectangular box is increased by 20 percent while its wid &nbs [#permalink] 30 Jul 2018, 10:45
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