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Scoring 329 on the GRE is not always about using more books, more courses, or a longer study plan. In this episode of GRE Success Talks, Ashutosh shares his GRE preparation strategy, study plan, and test-day experience, explaining how he kept his prep....
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Total No. of ways in which C is separated by atleast 1 letter = Total no. of permutations of CIRCLE - Total no. of permutations of CIRCLE when "C""C" are always together = (6!/2!)-5!=240
Hence E
Hence E
16 Dec 2025, 03:56
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Bunuel
Can I solve this as arrange IRLE in 4! ways and then given two C's are not together, imagine there is a gap betwen each of IRLE and hence 5 spaces which 2 Cs will position themselves leading to 5c2 ways
thus
4!*5C2
giving 240 as answer
Why I am not sure is given Cs are identical my impretation is given their position is unique no need to divide it by 2!. Please help
Can I solve this as arrange IRLE in 4! ways and then given two C's are not together, imagine there is a gap betwen each of IRLE and hence 5 spaces which 2 Cs will position themselves leading to 5c2 ways
thus
4!*5C2
giving 240 as answer
Why I am not sure is given Cs are identical my impretation is given their position is unique no need to divide it by 2!. Please help
