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14 Oct 2019, 08:13
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (00:46) correct
12%
(01:04)
wrong
based on 773
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The lunch menu at a certain restaurant contains 4 different entrees and 5 different side dishes. If a meal consists of 1 entree and 2 different side dishes, how many different meal combinations could be chosen from this menu?
(A) 10
(B) 20
(C) 40
(D) 80
(E) 100
(A) 10
(B) 20
(C) 40
(D) 80
(E) 100
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02 Aug 2021, 07:39
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Bunuel
Take the task of creating a meal and break it into stages.
Stage 1: Select an entree
There are four different entrees from which to choose.
So, we can complete stage 1 in 4 ways
Stage 2: Select 2 different side dishes
Since the order in which we select the 2 side dishes does not matter, we can use combinations.
We can select 2 side dishes from 5 side dishes in 5C2 ways = (5)(4)/(2)(1) = 10
So we can complete stage 2 in 10 ways
By the Fundamental Counting Principle (FCP), we can complete the 2 stages (and thus create a meal) in (4)(10) ways (= 40 ways)
Answer: C
Note: the FCP can be used to solve the MAJORITY of counting questions on the GMAT. So, be sure to learn it.
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14 Oct 2019, 09:38
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For the first side dish there 5 possible options, for the second only 4 (since we are looking for different combinations)
As it says "and", we have to multiply both combinations: 4 x (5x4) = 80 different combinations
As it says "and", we have to multiply both combinations: 4 x (5x4) = 80 different combinations
