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The median annual household income in a certain community of
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Updated on: 12 Aug 2012, 08:17
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The median annual household income in a certain community of 21 households is $50,000. If the mean income of a household increases by 10% per year over the next 2 years, what will the median income in the community be in 2 years? (A) $50,000 (B) $60,000 (C) $60,500 (D) $65,000 (E) Cannot be determined
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Originally posted by alimad on 21 Jun 2008, 21:01.
Last edited by Bunuel on 12 Aug 2012, 08:17, edited 1 time in total.
Edited the question and added the OA.




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Re: Median
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12 Aug 2012, 08:27
nikhil007 wrote: nmohindru wrote: The median annual household income in a certain community of 21 households is $50,000. If the mean income of a household increases by 10% per year over the next 2 years, what will the median income in the community be in 2 years?
(A) $50,000 (B) $60,000 (C) $60,500 (D) $65,000 (E) Cannot be determined
Should be e)
Mean increasing by certain % doesnt mean that median should increase by same %.
Median will only increase by same % if all data point move ahead by same % but increase of mean does not guarantee that all data points are moving by same % as well. Hi, I am a bit confused now, I thought this was the rule.. " If we increase or decrease each term in a set by the same percent: Mean will increase or decrease by the same percent. SD will increase or decrease by the same percent. so by that if mean increase by 10%, shouldn't all data points move by 10%..? By the way, above rule was also Highlighted in one of the post by Bunuel Here psquestionsaboutstandarddeviation85897.htmlam I missing a point here? can someone please explain the concept here? Reverse of this property is not true: if the mean increases by a certain percent it doesn't necessarily mean that each term increases by the same percent. Consider the following set: {1, 2, 3} > mean=median=2 and sum=6. Now, if we increase the mean by 100%, we increase the sum by 100%, so it'll become 12. But new set can be {0, 0, 12}: the third element increased and the first two elements decreased or {2, 2, 8}: the first and the third elements increased and the second remained the same... You can apply the same logic to the question at hand. Answer: E.
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Re: Median
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21 Jun 2008, 21:44
alimad wrote: The median annual household income in a certain community of 21 households is $50,000. If the mean income of a household increases by 10 % / year over the next 2 years, what will be the median income in the community be in 2 years?
50,000 60,000 60,500 65,000 cannot be determined.
Please respond with your answers. thanks I think E, I find no connection btw the increase and the median!
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Re: Median
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21 Jul 2008, 11:45
sondenso wrote: alimad wrote: The median annual household income in a certain community of 21 households is $50,000. If the mean income of a household increases by 10 % / year over the next 2 years, what will be the median income in the community be in 2 years?
50,000 60,000 60,500 65,000 cannot be determined.
Please respond with your answers. thanks I think E, I find no connection btw the increase and the median! I agree on E. The median could change depending on which incomes grow and by how much. For example, all incomes could grow by 10% each, meaning the median would also grow by 10%. Or the lowest income could grow by a huge number, moving it into the top half of incomes, which would completely change the median.



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Re: Median
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21 Jul 2008, 23:19
Should be e)
Mean increasing by certain % doesnt mean that median should increase by same %.
Median will only increase by same % if all data point move ahead by same % but increase of mean does not guarantee that all data points are moving by same % as well.



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Re: Median
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12 Aug 2012, 08:08
nmohindru wrote: Should be e)
Mean increasing by certain % doesnt mean that median should increase by same %.
Median will only increase by same % if all data point move ahead by same % but increase of mean does not guarantee that all data points are moving by same % as well. Hi, I am a bit confused now, I thought this was the rule.. " If we increase or decrease each term in a set by the same percent: Mean will increase or decrease by the same percent. SD will increase or decrease by the same percent. so by that if mean increase by 10%, shouldn't all data points move by 10%..? By the way, above rule was also Highlighted in one of the post by Bunuel Here psquestionsaboutstandarddeviation85897.htmlam I missing a point here? can someone please explain the concept here?
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Re: Median
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13 Aug 2012, 00:34
Bunuel wrote: Reverse of this property is not true: if the mean increases by a certain percent it doesn't necessarily mean that each term increases by the same percent.
Consider the following set: {1, 2, 3} > mean=median=2 and sum=6. Now, if we increase the mean by 100%, we increase the sum by 100%, so it'll become 12. But new set can be {0, 0, 12}: the third element increased and the first two elements decreased or {2, 2, 8}: the first and the third elements increased and the second remained the same...
You can apply the same logic to the question at hand.
Answer: E.
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Re: The median annual household income in a certain community of
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16 Aug 2012, 22:48
Answer is E, because there are different numbers in the set and we are not sure which side of the numbers in the set will be increased so the mean is increase by 10%. It could be the case that small number of higher end incomes increased a little or many low end incomes increased  it cannot be identified.
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Re: The median annual household income in a certain community of
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18 Aug 2012, 18:55
+1 E For example, if the highest value increase enough to increase in 10% the mean, the median will be the same. Other scenario is that every value increases in 10%, including the median. We cannot determine the new median.
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Re: The median annual household income in a certain community of
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15 Apr 2014, 13:34
But here the It is clearly mentioned that it is the mean income of a household..So here the mean refers to the average rise in income of the household members and not the mean of the incomes of the cimmunity..I think it is a typo error or I am missing something here... Correct me if I am wrong
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Re: The median annual household income in a certain community of
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15 Apr 2014, 13:47
JusTLucK04 wrote: But here the It is clearly mentioned that it is the mean income of a household..So here the mean refers to the average rise in income of the household members and not the mean of the incomes of the cimmunity..I think it is a typo error or I am missing something here... Correct me if I am wrong We can not determine the median income from provided data. The median annual household income in a certain community of 21 households is $50,000. If the mean income of a household increases by 10% per year over the next 2 years, what will the median income in the community be in 2 years? As we do not know that distribution of income is uniform we can not conclude that median = mean from provided data we got that 11th household is earning $50,000 Let mean = x increase by 10% for next 2 years... we do not whether every house hold income has increased or few has increased or for few remain constant or reduced.. its easy to get 10% rise in mean by just increasing income for few households ..thus we can not construct data set and we can not get median. Answer is E.
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Re: The median annual household income in a certain community of
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15 Apr 2014, 13:57
PiyushK wrote: JusTLucK04 wrote: But here the It is clearly mentioned that it is the mean income of a household..So here the mean refers to the average rise in income of the household members and not the mean of the incomes of the cimmunity..I think it is a typo error or I am missing something here... Correct me if I am wrong We can not determine the median income from provided data. The median annual household income in a certain community of 21 households is $50,000. If the mean income of a household increases by 10% per year over the next 2 years, what will the median income in the community be in 2 years? As we do not know that distribution of income is uniform we can not conclude that median = mean from provided data we got that 11th household is earning $50,000 Let mean = x increase by 10% for next 2 years... we do not whether every house hold income has increased or few has increased or for few remain constant or reduced.. its easy to get 10% rise in mean by just increasing income for few households ..thus we can not construct data set and we can not get median. Answer is E. Bahh..My bad..I read it extremely wrongly. ...I was referring to the income rise from household members.. Don't know where did that come from..Guess I did better
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Re: The median annual household income in a certain community of
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14 May 2015, 11:07
E. Mean and median aren't interchangeable. The mean can have a very different value from the median if there are many households with very high or low incomes. Without the value of the mean provided, there's no way to predict what it will be.



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Re: The median annual household income in a certain community of
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25 Jul 2017, 01:14
The answer is E. The mean can be changed by changing one or more observations. As correctly pointed out in posts above, 10% increase in mean over two years doesn't mean that each observation increases by 10%. Therefore median may or may not be 50,000 after two years. When you assume the theory that each observation is changing by 10% per year, answer comes out to be $60,500.



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