Bunuel wrote:

The number N is 5H72, the hundred's digit being represented by H. What is the value of H?

(1) N is divisible by 4.

(2) N is divisible by 9.

(1) For a number to be divisible by 4, its last two digits must be divisible by 4. So in case of 5H72, since last two digits are divisible by 4 (72 is a multiple of 4), 5H72 WILL be divisible by 4, irrespective of the value of H (meaning H can take any value from 0 to 9 doesnt matter). So Insufficient.

(2) For a number to be divisible by 9, its sum of digits must be divisible by 9. So 5+H+7+2 = 14+H must be divisible by 9. We can see that H can thus take only one value of '4', which will make sum of digits as 18, and thus divisible by 9. Sufficient.

Hence

B answer