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Question Stats:
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The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H. If the total number of rooms at Hotel G and Hotel H is 425, what is the number of rooms at Hotel G?
(A) 140
(B) 180
(C) 200
(D) 240
(E) 280
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(A) 140
(B) 180
(C) 200
(D) 240
(E) 280
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Let G be the no. of rooms at hotel G and H be the no. of rooms at hotel H.
G = 2H - 10;
G + H = 425; H = 425 - G;
Since we have to find G,
G = 2H - 10 = 2(425 - G) - 10
G = 850 - 2G - 10;
3G = 840;
G = 840/3
G = 280;
Ans is (E).
G = 2H - 10;
G + H = 425; H = 425 - G;
Since we have to find G,
G = 2H - 10 = 2(425 - G) - 10
G = 850 - 2G - 10;
3G = 840;
G = 840/3
G = 280;
Ans is (E).
General Discussion
SOLUTION
The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H. If the total number of rooms at Hotel G and Hotel H is 425, what is the number of rooms at Hotel G?
(A) 140
(B) 180
(C) 200
(D) 240
(E) 280
The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H --> G = 2H - 10;
The total number of rooms at Hotel G and Hotel His 425 --> G + H = 425.
Solving gives G = 280.
Answer: E.
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The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H. If the total number of rooms at Hotel G and Hotel H is 425, what is the number of rooms at Hotel G?
(A) 140
(B) 180
(C) 200
(D) 240
(E) 280
The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H --> G = 2H - 10;
The total number of rooms at Hotel G and Hotel His 425 --> G + H = 425.
Solving gives G = 280.
Answer: E.
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• Rules: Quantitative | Verbal
Posts: 4,849
Bunuel
A very good contender for back solving. Let us start with option C.
Hotel G Hotel H Total
(A) 140
(B) 180
(C) 200 210/2 = 105 200 + 105 = 305
(D) 240
(E) 280
We were supposed to get 425 however we got 305 hence we should move down
Hotel G Hotel H Total
(A) 140
(B) 180
(C) 200 210/2 = 105 200 + 105 = 305
(D) 240
(E) 280 290/2 = 145 280 + 145 = 425 (BINGO!)
Pushpinder Gill
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Last visit: 31 Oct 2021
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CrackVerbalGMAT
The solution looks very elegant.
Do you advise to start back solving from Option (E), since G/(G+H) is close to 2/3 or, the solution is approximately close to \(2/3(425)\)
Posts: 4,849
arunspanda
I would advise you to start with option C and then move up or down according to the condition as the answer options are always in ascending or descending order.
WoundedTiger
Joined: 25 Apr 2012
Last visit: 03 Jan 2026
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The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H. If the total number of rooms at Hotel G and Hotel His 425, what is the number of rooms at Hotel G?
(A) 140
(B) 180
(C) 200
(D) 240
(E) 280
Sol: Let no. of room in Hotel H be X. Then No. of rooms in Hotel G is 10 less than twice the no. of rooms at Hotel H i.e No. of rooms =2X-10
Given
X+2X-10=425 or 3x=435 X=145---->No. of rooms in Hotel H
Hotel G = 2*145-10= 280
Ans E
(A) 140
(B) 180
(C) 200
(D) 240
(E) 280
Sol: Let no. of room in Hotel H be X. Then No. of rooms in Hotel G is 10 less than twice the no. of rooms at Hotel H i.e No. of rooms =2X-10
Given
X+2X-10=425 or 3x=435 X=145---->No. of rooms in Hotel H
Hotel G = 2*145-10= 280
Ans E
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Expert reply
Posts: 22,738
Bunuel
We can let the number of rooms in hotel G = g and the number of rooms in hotel H = h and create the two equations:
g = 2h - 10
and
g + h = 425
Substituting the first equation for g in the second equation, we have:
2h - 10 + h = 425
3h = 435
h = 145
So g = 2(145) - 10 = 280.
Answer: E
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Bunuel
We can also solve the question using 1 variable
Let x = number of rooms at Hotel H
The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H
So, 2x - 10 = number of rooms at Hotel G
The total number of rooms at Hotel G and Hotel H is 425
We can write: x + (2x - 10) = 425
Simplify: 3x - 10 = 425
Solve: x = 145
2x - 10 = number of rooms at Hotel G
So, the number of rooms at Hotel G = 2(145) - 10
= 280
Answer: E
Cheers,
Brent
Kinshook
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Joined: 03 Jun 2019
Last visit: 13 Sep 2026
Posts: 6,129
Location: India
Schools: HBS '28 CBS '26 Wharton '26
GMAT 1: 690 Q50 V34
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Bunuel
Given:
1. The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H.
2. The total number of rooms at Hotel G and Hotel H is 425
Asked: What is the number of rooms at Hotel G?
Let the number of rooms at hotel G be g and at hotel H be h.
g = 2h -10 ; \(h = \frac{g+10}{2}\). (1)
g + h = 425 (2)
\(g + \frac{g + 10}{2} = 425\)
3g + 10 = 850
g = 840/3 = 280
IMO E
GMAT 1: 750 Q49 V42
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Posts: 163
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