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The number of touchscreen personal organizers currently in stock is p

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The number of touchscreen personal organizers currently in stock is p [#permalink]

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New post 20 Jan 2015, 07:21
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The number of touchscreen personal organizers currently in stock is p times what it was at the beginning of the year. If the number of touchscreen organizers currently in stock is t and the number in stock at the beginning of the year is x (where t, x and p do not equal zero), are there more touchscreen personal organizers in stock now than there were at the beginning of the year?

(1) p > x

(2) tp > t

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[Reveal] Spoiler: OA

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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]

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New post 20 Jan 2015, 08:53
Bunuel wrote:
The number of touchscreen personal organizers currently in stock is p times what it was at the beginning of the year. If the number of touchscreen organizers currently in stock is t and the number in stock at the beginning of the year is x (where t, x and p do not equal zero), are there more touchscreen personal organizers in stock now than there were at the beginning of the year?

(1) p > x

(2) tp > t

Kudos for a correct solution.


question is t > x? assume that x=int; t=int; p: case 1 p=int; case 2 0<p<1. t=px

1st statement; p > x Since x is an integer case 2 of p won't happen, meaning that p is an integer --> t = x(int) --> t > x.

2nd statement: tp>t --> t(p-1)>0 --> t > 0 we already know that; p>1. Case 2 of p won't happen. Least value of p = 2 --> t=2x --> t > x.

Answer is D.
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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]

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New post 26 Jan 2015, 05:29
Bunuel wrote:
The number of touchscreen personal organizers currently in stock is p times what it was at the beginning of the year. If the number of touchscreen organizers currently in stock is t and the number in stock at the beginning of the year is x (where t, x and p do not equal zero), are there more touchscreen personal organizers in stock now than there were at the beginning of the year?

(1) p > x

(2) tp > t

Kudos for a correct solution.


The correct answer is D.
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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]

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New post 12 May 2015, 12:44
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Stock at the beginning of the year is x

and , t = p*x where t,p,and x are not equal to Zero

1) If p>x ,
then t > x ......... So this statement is sufficient

2) If tp > t ,
then, p > 1 which again gives t > x ............ sufficient

Answer D :)

Bunuel wrote:
The number of touchscreen personal organizers currently in stock is p times what it was at the beginning of the year. If the number of touchscreen organizers currently in stock is t and the number in stock at the beginning of the year is x (where t, x and p do not equal zero), are there more touchscreen personal organizers in stock now than there were at the beginning of the year?

(1) p > x

(2) tp > t

Kudos for a correct solution.

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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]

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New post 12 May 2015, 22:22
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The question is asking us if t > x

That is, if px > x

Now, since x denotes the number of items, x must be a non-negative integer (because you cannot have -1 devices or 0.5 devices) . We are already given that x is not equal to zero. This means, x is a positive integer for sure (the minimum possible value of x is 1)

So, we can safely divide both sides of the above inequality with x, without impacting the sign of inequality.


And thus, the question simplifies to: Is p > 1?

St. 1 says: p > x

This means, p > (positive integer x, whose minimum possible value is 1)

=> p > 1 for sure

Sufficient.

St. 2 says: tp > t

As explained above for x, t also is a positive integer for sure. So, we can safely divide both sides of the above inequality with t, without impacting the sign of inequality.

We get: p > 1

Sufficient.

Hope this was useful! :)

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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]

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New post 13 May 2015, 23:42
Bunuel wrote:
The number of touchscreen personal organizers currently in stock is p times what it was at the beginning of the year. If the number of touchscreen organizers currently in stock is t and the number in stock at the beginning of the year is x (where t, x and p do not equal zero), are there more touchscreen personal organizers in stock now than there were at the beginning of the year?

(1) p > x

(2) tp > t


Ans: D
Solution: we know numbers x=number of TPO at the begining, t=TPO at the end of the year, p=multiplier
we also know that these numbers are integers and only p can be any value except zero. [t=p*x given]
1) p>x ; if p>x then t>x, because x is integer and non negative. as you cannot have -1 TPO. (I think) [Sufficient]
2) tp>t ; t(p-1)>0 ;
so now for this to be true,
t>0 & (p-1)>0 OR t<0 & (p-1)<0
as we know t>0 second condition does not follow and with first condition we know that P>1
so this statement alone is sufficient to ans the question. [Sufficient]

Ans. D [Both statement alone are sufficient to answer the question]
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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]

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New post 25 Feb 2016, 20:22
Bunuel wrote:
The number of touchscreen personal organizers currently in stock is p times what it was at the beginning of the year. If the number of touchscreen organizers currently in stock is t and the number in stock at the beginning of the year is x (where t, x and p do not equal zero), are there more touchscreen personal organizers in stock now than there were at the beginning of the year?

(1) p > x

(2) tp > t

Kudos for a correct solution.


ok, so we are given:
t=px.
where t, p, and x - are not zero.

1. p>x. since x can't be zero, suppose p=x. px=x^2. x^2 is always greater than x when x is greater than 0. note that it can't be a non-integer, since we are speaking about touchscreen personal organizers, and these cannot be half/third/etc.

so 1 is sufficient.

2. tp>t.
ok, we know t=px
p=t/x
t*t/x>t
t^2/x >t
knowing that t is not 0, and can't be negative - touchscreen personal organizers negative? :D
we can divide by t:
t/x>1.
so t>x. sufficient.

D.

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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]

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New post 25 Feb 2016, 23:32
From the given facts,
t = p *x

where t, p and x are positive and

t and x are integers >= 1

1) If p > x,
p has to be > 1

This implies t > x (Statement 1 is sufficient)

2) tp >t

Since t can not be equal to zero,

We can cancel out t,

which leaves,

p > 1

again, this shows t > x

So statement 2 is sufficient as well.

Answer : D
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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]

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Re: The number of touchscreen personal organizers currently in stock is p   [#permalink] 25 Sep 2017, 11:57
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