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The number of touchscreen personal organizers currently in stock is p [#permalink]
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20 Jan 2015, 07:21
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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]
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20 Jan 2015, 08:53
Bunuel wrote: The number of touchscreen personal organizers currently in stock is p times what it was at the beginning of the year. If the number of touchscreen organizers currently in stock is t and the number in stock at the beginning of the year is x (where t, x and p do not equal zero), are there more touchscreen personal organizers in stock now than there were at the beginning of the year?
(1) p > x
(2) tp > t
Kudos for a correct solution. question is t > x? assume that x=int; t=int; p: case 1 p=int; case 2 0<p<1. t=px 1st statement; p > x Since x is an integer case 2 of p won't happen, meaning that p is an integer > t = x(int) > t > x. 2nd statement: tp>t > t(p1)>0 > t > 0 we already know that; p>1. Case 2 of p won't happen. Least value of p = 2 > t=2x > t > x. Answer is D.
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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]
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26 Jan 2015, 05:29



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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]
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12 May 2015, 12:44
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Stock at the beginning of the year is xand , t = p*x where t,p,and x are not equal to Zero1) If p>x , then t > x ......... So this statement is sufficient 2) If tp > t , then, p > 1 which again gives t > x ............ sufficient Answer D Bunuel wrote: The number of touchscreen personal organizers currently in stock is p times what it was at the beginning of the year. If the number of touchscreen organizers currently in stock is t and the number in stock at the beginning of the year is x (where t, x and p do not equal zero), are there more touchscreen personal organizers in stock now than there were at the beginning of the year?
(1) p > x
(2) tp > t
Kudos for a correct solution.
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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]
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12 May 2015, 22:22
The question is asking us if t > xThat is, if px > x Now, since x denotes the number of items, x must be a nonnegative integer (because you cannot have 1 devices or 0.5 devices) . We are already given that x is not equal to zero. This means, x is a positive integer for sure (the minimum possible value of x is 1)
So, we can safely divide both sides of the above inequality with x, without impacting the sign of inequality.And thus, the question simplifies to: Is p > 1?St. 1 says: p > xThis means, p > (positive integer x, whose minimum possible value is 1) => p > 1 for sure Sufficient. St. 2 says: tp > tAs explained above for x, t also is a positive integer for sure. So, we can safely divide both sides of the above inequality with t, without impacting the sign of inequality.We get: p > 1 Sufficient. Hope this was useful! Japinder
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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]
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13 May 2015, 23:42
Bunuel wrote: The number of touchscreen personal organizers currently in stock is p times what it was at the beginning of the year. If the number of touchscreen organizers currently in stock is t and the number in stock at the beginning of the year is x (where t, x and p do not equal zero), are there more touchscreen personal organizers in stock now than there were at the beginning of the year?
(1) p > x
(2) tp > t
Ans: D Solution: we know numbers x=number of TPO at the begining, t=TPO at the end of the year, p=multiplier we also know that these numbers are integers and only p can be any value except zero. [t=p*x given] 1) p>x ; if p>x then t>x, because x is integer and non negative. as you cannot have 1 TPO. (I think) [Sufficient] 2) tp>t ; t(p1)>0 ; so now for this to be true, t>0 & (p1)>0 OR t<0 & (p1)<0 as we know t>0 second condition does not follow and with first condition we know that P>1 so this statement alone is sufficient to ans the question. [Sufficient] Ans. D [Both statement alone are sufficient to answer the question]
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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]
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25 Feb 2016, 20:22
Bunuel wrote: The number of touchscreen personal organizers currently in stock is p times what it was at the beginning of the year. If the number of touchscreen organizers currently in stock is t and the number in stock at the beginning of the year is x (where t, x and p do not equal zero), are there more touchscreen personal organizers in stock now than there were at the beginning of the year?
(1) p > x
(2) tp > t
Kudos for a correct solution. ok, so we are given: t=px. where t, p, and x  are not zero. 1. p>x. since x can't be zero, suppose p=x. px=x^2. x^2 is always greater than x when x is greater than 0. note that it can't be a noninteger, since we are speaking about touchscreen personal organizers, and these cannot be half/third/etc. so 1 is sufficient. 2. tp>t. ok, we know t=px p=t/x t*t/x>t t^2/x >t knowing that t is not 0, and can't be negative  touchscreen personal organizers negative? :D we can divide by t: t/x>1. so t>x. sufficient. D.



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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]
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25 Feb 2016, 23:32
From the given facts, t = p *x where t, p and x are positive and t and x are integers >= 1 1) If p > x, p has to be > 1 This implies t > x (Statement 1 is sufficient) 2) tp >t Since t can not be equal to zero, We can cancel out t, which leaves, p > 1 again, this shows t > x So statement 2 is sufficient as well. Answer : D
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Re: The number of touchscreen personal organizers currently in stock is p [#permalink]
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25 Sep 2017, 11:57
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