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22 Dec 2020, 10:00
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
75% (02:03) correct
25%
(02:31)
wrong
based on 61
sessions
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Not Attempted Yet
The numbers –2, x, –32 are the first three terms in a geometric progression. Which of the following could be the sixth term in the progression? (A geometric progression, also known as a geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-one number called the common ratio)
(A) –4,096
(B) –2,048
(C) –1,024
(D) 512
(E) 1,024
(A) –4,096
(B) –2,048
(C) –1,024
(D) 512
(E) 1,024
bM22
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22 Dec 2020, 10:23
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Bunuel
First, we need to find the common ratio:
in a G.P. = -32/x = x/-2
=> x^2 = 64
=> x = +/- 8
Now 2 cases arise:
Case 1: Terms of G.P. are: -2,8,-32 = > common ratio = -4.
=> 6th term = a*(r^(n-1)) where a is the first term, r is the common ratio and n is the no. of term we are looking for.
=> 6th term = -2 * (-4)^5 = -2* (-2^10) = 2^11 = 2048 === > Not mentioned in the options
Case 1: Terms of G.P. are: -2, -8,-32 = > common ratio = 4.
=> 6th term = -2 * (4)^5 = -2* (2^10) = -2^11 = -2048
Answer is B.
22 Dec 2020, 10:30
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Given, -2, x and -32 are in GP.
a= -2, x = (-2)*r and -32 =(-2)*r^2 or, r=4
So, 6th term = a*r^5 = (-2)* 4^5 = -2048.
I think B.
a= -2, x = (-2)*r and -32 =(-2)*r^2 or, r=4
So, 6th term = a*r^5 = (-2)* 4^5 = -2048.
I think B.
