Summer is Coming! Join the Game of Timers Competition to Win Epic Prizes. Registration is Open. Game starts Mon July 1st.

 It is currently 17 Jul 2019, 20:20

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# The operation # is defined in the following way for any two numbers

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 56277
The operation # is defined in the following way for any two numbers  [#permalink]

### Show Tags

08 Mar 2018, 02:05
00:00

Difficulty:

15% (low)

Question Stats:

88% (01:35) correct 13% (02:16) wrong based on 44 sessions

### HideShow timer Statistics

The operation # is defined in the following way for any two numbers: p#q = (p - q)(q - p). If p#q = -1, then which of the following are true?

I. p could equal 5 and q could equal 4
II. p could equal 4 and q could equal 5
III. p could equal 1 and q could equal -1
IV. p could equal -1 and q could equal 1

(A) I and II only
(B) I and III only
(C) II and IV only
(D) III and IV only
(E) I, II, III, IV

_________________
Math Expert
Joined: 02 Sep 2009
Posts: 56277
Re: The operation # is defined in the following way for any two numbers  [#permalink]

### Show Tags

08 Mar 2018, 02:10
Bunuel wrote:
The operation # is defined in the following way for any two numbers: p#q = (p - q)(q - p). If p#q = -1, then which of the following are true?

I. p could equal 5 and q could equal 4
II. p could equal 4 and q could equal 5
III. p could equal 1 and q could equal -1
IV. p could equal -1 and q could equal 1

(A) I and II only
(B) I and III only
(C) II and IV only
(D) III and IV only
(E) I, II, III, IV

13. Functions

For more check below:
ALL YOU NEED FOR QUANT ! ! !
Ultimate GMAT Quantitative Megathread
_________________
Senior PS Moderator
Joined: 26 Feb 2016
Posts: 3360
Location: India
GPA: 3.12
Re: The operation # is defined in the following way for any two numbers  [#permalink]

### Show Tags

08 Mar 2018, 03:48
Since the operation # is defined as p#q = (p - q)(q - p),
and we are given that p#q = -1, then testing the following values, we get

I. p could equal 5 and q could equal 4 -> (p - q)(q - p) = (5-4)(4-5) = -1
II. p could equal 4 and q could equal 5 -> (p - q)(q - p) = (4-5)(5-4) = -1
III. p could equal 1 and q could equal -1 -> (p - q)(q - p) = (1-(-1))(-1-1) = -4
IV. p could equal -1 and q could equal 1 > (p - q)(q - p) = (-1-1)(1-(-1)) = -4

Therefore, Option A(I and II only) is always true for the operation # such that p#q = -1
_________________
You've got what it takes, but it will take everything you've got
Manager
Joined: 23 Sep 2016
Posts: 236
Re: The operation # is defined in the following way for any two numbers  [#permalink]

### Show Tags

08 Mar 2018, 23:46
Bunuel wrote:
The operation # is defined in the following way for any two numbers: p#q = (p - q)(q - p). If p#q = -1, then which of the following are true?

I. p could equal 5 and q could equal 4
II. p could equal 4 and q could equal 5
III. p could equal 1 and q could equal -1
IV. p could equal -1 and q could equal 1

(A) I and II only
(B) I and III only
(C) II and IV only
(D) III and IV only
(E) I, II, III, IV

IMO A
IF p#q = (p - q)(q - p)
AND P#Q=-1
THEN
I 1*-1 yes
II -1*1 yes
III 2*-2 no
and no need to check last one as we can see there is no option with I, II and IV
So A is the answer
Re: The operation # is defined in the following way for any two numbers   [#permalink] 08 Mar 2018, 23:46
Display posts from previous: Sort by

# The operation # is defined in the following way for any two numbers

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne