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31 May 2017, 03:49
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
96% (00:29) correct
4%
(00:51)
wrong
based on 24
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The perimeter of a square is equal to the perimeter of a rectangle whose length and width are 6m and 4m, respectively. The side of the square is
(A) 3m
(B) 4m
(C) 5m
(D) 6m
(E) 7m
(A) 3m
(B) 4m
(C) 5m
(D) 6m
(E) 7m
Source: Nova GMAT
Difficulty Level: 550
Difficulty Level: 550
31 May 2017, 03:56
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If l and b are length and width of the rectangle, and side of square is a
2(l+b) = 4a
Here l=6,b=4
So, 4a = 20 or side of the square is 5m(Option C)
Sent from my ONEPLUS A3003 using GMAT Club Forum mobile app
2(l+b) = 4a
Here l=6,b=4
So, 4a = 20 or side of the square is 5m(Option C)
Sent from my ONEPLUS A3003 using GMAT Club Forum mobile app
31 May 2017, 05:43
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Perimeter of rectangle= 2(L+B)
= 2(6+4)= 20
Perimeter of rectangle= Perimeter of square
Perimeter of square= 4*side
4S= 20
Side= \(\frac{20}{4}\)=5
Answer: C.
Kudos please if you like my explanation!
= 2(6+4)= 20
Perimeter of rectangle= Perimeter of square
Perimeter of square= 4*side
4S= 20
Side= \(\frac{20}{4}\)=5
Answer: C.
Kudos please if you like my explanation!
