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29 May 2017, 04:51
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The perimeter of the outside of truck tire R is 7/8 the perimeter of the outside of truck tire T. What is the area of the outside of truck tire T?
(1) The diameter of the outside of truck tire R is 1.75 feet.
(2) The radius of the outside of truck tire T is 1 foot.
(1) The diameter of the outside of truck tire R is 1.75 feet.
(2) The radius of the outside of truck tire T is 1 foot.
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29 May 2017, 06:42
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SajjadAhmad
The perimeter of the outside of truck tire R is 7/8 the perimeter of the outside of truck tire T. What is the area of the outside of truck tire T?
(1) The diameter of the outside of truck tire R is 1.75 feet.
(2) The radius of the outside of truck tire T is 1 foot.
(1) The diameter of the outside of truck tire R is 1.75 feet.
(2) The radius of the outside of truck tire T is 1 foot.
I did not understand the question completely but here is my solution:
(Considered "outside of truck tire" = circle)
Given:
Perimeter of circle R = 7/8 Perimeter of circle T
=> 2*pie* R = (7/8) * 2*pie* T (considering R as radius of circle R and T as radius of circle T)
=>8 R = 7 T
To find area of circle T i.e we need to find the value of radius T
Statement A: The diameter of the outside of truck tire R is 1.75 feet
Diameter = 1.75 => Radius (R) = 0.875
Thus T = (8/7) * R = 1 foot
Sufficient
Statement B: The radius of the outside of truck tire T is 1 foot
Since we know the radius of T, area can be found out.
Sufficient
Thus both sufficient, Answer option D
29 May 2017, 06:51
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Let radius of Truck tire R = r
Let radius of Truck tire T = t
given: r = \(\frac{7t}{8}\) { Cancelling the 2pi both the sides)
St1: gives r = 1.75 so t comes out to be 1
Area of Truck tire T = pi \(t^2\) = 3.14 : Sufficient
St2 : gives t = 1
Area of Truck tire T = pi \(t^2\) = 3.14 : Sufficient
ANs: D
Let radius of Truck tire T = t
given: r = \(\frac{7t}{8}\) { Cancelling the 2pi both the sides)
St1: gives r = 1.75 so t comes out to be 1
Area of Truck tire T = pi \(t^2\) = 3.14 : Sufficient
St2 : gives t = 1
Area of Truck tire T = pi \(t^2\) = 3.14 : Sufficient
ANs: D
