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# The perimeter of the rectangle shown is 18 feet. What is the area, in

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Math Expert
Joined: 02 Sep 2009
Posts: 50036
The perimeter of the rectangle shown is 18 feet. What is the area, in  [#permalink]

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29 Mar 2018, 23:50
00:00

Difficulty:

15% (low)

Question Stats:

93% (00:59) correct 7% (00:00) wrong based on 38 sessions

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The perimeter of the rectangle shown is 18 feet. What is the area, in square feet, of the rectangle?

(A) 9
(B) 10
(C) 20
(D) 30
(E) 40

Attachment:

2018-03-30_1049.png [ 4.71 KiB | Viewed 401 times ]

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Re: The perimeter of the rectangle shown is 18 feet. What is the area, in  [#permalink]

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30 Mar 2018, 00:07
Bunuel wrote:

The perimeter of the rectangle shown is 18 feet. What is the area, in square feet, of the rectangle?

(A) 9
(B) 10
(C) 20
(D) 30
(E) 40

Attachment:
2018-03-30_1049.png

2(l+b) = perimter

2(10/x + 8 x) =18
2 x 18 = 18 x X
X= 2

so l and b are 5 and 4

area = l*b = 20
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Re: The perimeter of the rectangle shown is 18 feet. What is the area, in  [#permalink]

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30 Mar 2018, 00:58
Perimeter of rectangle= 2(L+B)= 18

= 2($$\frac{8}{x}$$+$$\frac{10}{x}$$)= 18

= 2($$\frac{8+10}{x}$$)= 18

= 2($$\frac{18}{x}$$) =18

x=2

Length= $$\frac{10}{2}$$= 5

Breadth= $$\frac{8}{2}$$= 4

Area= 5*4= 20

$$Answer: C.$$
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Re: The perimeter of the rectangle shown is 18 feet. What is the area, in &nbs [#permalink] 30 Mar 2018, 00:58
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