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805+ (Hard)|   Geometry|      
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robinbjoern
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The playing area for a certain outdoor game requires markings accordin 09 Jul 2020, 22:13
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noTh1ng
Radius of the circle: 3

Perimeter of the circle: 2πr = 6π
Perimeter of the square: 3*4 = 12
Perimeter of the triangle: 9+12+15 = 36

12+36+6π = 48+6π and this is approximately 67. Answer D
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but you count 2 sides of the square double.
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madzaka
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The playing area for a certain outdoor game requires markings accordin 09 Jul 2020, 22:49
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peachfuzz
Bunuel

Note: figure not drawn to scale

The playing area for a certain outdoor game requires markings according to the figure shown. The ratio of AB:BC:AC is 3:4:5 ; O is the midpoint of the circle, R and Q are both points on the circle with center O and corners of square OBQR. If QB is 1/3 of AB and a person running in a straight line from Q to R travels 3√2 meters, approximately how many meters of paint are required to paint the playing area on a surface (assume the lines have negligible width)?


Ratio of the larger triangle is 3x to 4x to 5x
The small triangle is a 45 45 90 triangle so x×sqrt (2) = 3×sqrt (2)
×=3

The sides of the larger triangle is 9, 12, 15

A= (1/2)×9×12
=54

Answer
(A) 54
Not sure why there is a pi after 54, should be just 54
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This answer is wrong. You dont calculate the surface, you calculate the length of all the lines
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warriortx
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GMAT 1: 760 Q48 V47
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The playing area for a certain outdoor game requires markings accordin 22 Jul 2020, 06:06
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Question is not clear! Should specify which part of the drawing is the 'playing field'.
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