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# The point C divides line segment AB such that AC=3*CB. If

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The point C divides line segment AB such that AC=3*CB. If [#permalink]

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15 Oct 2003, 05:32
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The point C divides line segment AB such that AC=3*CB. If point A(3,2)
B(6,4). Find the cordinates of point C.

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CEO
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15 Oct 2003, 07:24
Vicky wrote:
The point C divides line segment AB such that AC=3*CB. If point A(3,2)
B(6,4). Find the cordinates of point C.

i get (3/2,1)

i used distance formula,pythagorous theorem, and finally similarity.

thanks vicks

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15 Oct 2003, 08:30
I got (3┬╛, 2┬╜).

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15 Oct 2003, 08:38
wonder_gmat wrote:
I got (3┬╛, 2┬╜).

no wonder, i got the ratio backwards..never mind...

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16 Oct 2003, 02:28

The point C divides line segment AB such that AC=3*CB. If point A(3,2)
B(6,4). Find the cordinates of point C.

A) (3/2, 1)
B) (3┬╛, 2┬╜)
C) (9/2, 3)
D) (21/4, 7/2)
E) (15/4, 5/2)

Hint: A & B are not correct. praet and wonder try again...
thanks

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16 Oct 2003, 02:42
In other words AB is divided by four equal segments and AC is one of them.
Let F be a midpoint of AB. F's X=3+(6-3)/2=4.5, and F's Y=2+(4-2)/2=3.
C is a midpoint of F.

C's X=3+(4.5-3)/2=3.75, and C's Y=2+(3-2)/2=2.5

C (3.75; 2.5)

Looks like B.

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16 Oct 2003, 05:41
Vicky wrote:

The point C divides line segment AB such that AC=3*CB. If point A(3,2)
B(6,4). Find the cordinates of point C.

A) (3/2, 1)
B) (3┬╛, 2┬╜)
C) (9/2, 3)
D) (21/4, 7/2)
E) (15/4, 5/2)

Hint: A & B are not correct. praet and wonder try again...
thanks

Aren't (B) and (E) the same?

(D) can't be it, because too big. (C) has a chance but that's a little big. (E) seems like a good choice but it's the same as (B).

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16 Oct 2003, 09:14
I vote for D.

Let AB be divided into 4 parts AP, PQ, QC and CB such that AC = 3 * CB

Then AQ = QB So, Q = ((3 + 6)/2, (2+4)/2) = (4.5, 3)

C will be the mid point of Q and B

i.e ((4.5 + 6)/2, (3+4)/2) = (5.25, 3.5) = (21/4, 7/2)

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17 Oct 2003, 07:01
good try by all. amar's answer is correct.
Stolyar the only mistake that u did was to find C such that AC = 1/3*CB.
Question asks for AC = 3*CB.
Find the midpoint of AB (say M) M = (9/2,3) [avg. of coordinates of A & B]

Now, find the midpoint of MB (say C) C = (21/4,7/2) [avg. of coordinates of M & B]. Point C divides AB in the ratio 3:1.

This was easy. What if the given ratio is 3:2.
Then above method will be more involved and lengthy.
In such problems i wud directly use the following formula:

If point C divides line segemnt joining A(x1, y1) and B(x2,y2) in the ratio
m:n , then cordinates of C is given by:

(m*x2 + n*x1)/(m+n), (m*y2 + n*y1)/(m+n)

For above example: cordinates of C are:
(3*6+ 1*3)/(3+1), (3*4+ 1*2)/(3+1)
= 21/4,7/2

thanks.

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01 Nov 2003, 08:40
Center of (3,2) and (6,4) is (3+6/2,4+2/2) = (9/2,3)--this is the center of the A and B. No find the center of (9/2,3) and (6,4) it will give (21/4,7/2)

Bhai

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23 May 2004, 09:16
Vicky wrote:

The point C divides line segment AB such that AC=3*CB. If point A(3,2)
B(6,4). Find the cordinates of point C.

A) (3/2, 1)
B) (3Â¾, 2Â½)
C) (9/2, 3)
D) (21/4, 7/2)
E) (15/4, 5/2)

Hint: A & B are not correct. praet and wonder try again...
thanks

Find C, such that it cuts segment AB in m:n
A(x1, y1)
B(x2, y2)
P(x, y)
AC/CB = m/n=1/3

Then C(x) = (nx1+mx2)/(m+n)=(9+6)/4=3 3/4
C(y) = (ny1+my2)/(m+n)=(6+4)/4=2 1/2

What's wrong with this???

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23 May 2004, 10:44
edited by praet: virtual , i edited your post to make your answer more clear. mirhaque, do you see the error in your solution?

mirhaque wrote :

Find C, such that it cuts segment AB in m:n
A(x1, y1)
B(x2, y2)
P(x, y)

AC/CB = m/n=1/3 .........

Virtual's comment : wrong here AC/CB is 3/1 an not 1/3 .

Then C(x) = (nx1+mx2)/(m+n)=(9+6)/4=3 3/4
C(y) = (ny1+my2)/(m+n)=(6+4)/4=2 1/2

What's wrong with this???

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23 May 2004, 15:51
Virtual wrote:
edited by praet: virtual , i edited your post to make your answer more clear. mirhaque, do you see the error in your solution?

mirhaque wrote :

Find C, such that it cuts segment AB in m:n
A(x1, y1)
B(x2, y2)
P(x, y)

AC/CB = m/n=1/3 .........

Virtual's comment : wrong here AC/CB is 3/1 an not 1/3 .

Then C(x) = (nx1+mx2)/(m+n)=(9+6)/4=3 3/4
C(y) = (ny1+my2)/(m+n)=(6+4)/4=2 1/2

What's wrong with this???

thanks a lot!

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23 May 2004, 15:51
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