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Bunuel
The price of an item is discounted 10 percent on day 1 of a sale. On day 2, the item is discounted another 10 percent, and on day 3, it is discounted an additional 20 percent. The price of the item on day 3 is what percentage of the sale price on day 1?

A. 28%
B. 40%
C. 64.8%
D. 70%
E. 72%

intial 100$
day 1= 90$
day 2= 81 $
day 3 = 64.8$
so % of day 3 of day 1= 64.8/90 ; 72%
IMO E
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Bunuel
The price of an item is discounted 10 percent on day 1 of a sale. On day 2, the item is discounted another 10 percent, and on day 3, it is discounted an additional 20 percent. The price of the item on day 3 is what percentage of the sale price on day 1?

A. 28%
B. 40%
C. 64.8%
D. 70%
E. 72%


If n = original price, then with all the discounts, the price of the item is:

n(0.9)(0.9)(0.8) = 0.648n

Thus, the answer is 0.648/0,.9 = 0.72 = 72%

Answer: E
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The question asks for the percentage of the price in day 3 to the price in day 1.
Therefore, if P1 and P3 are the prices of the item in day 1 and 3 respectively, we need to answer P3/P1. We can see that we actually dont care about the price reduction in the first day since the answer will not depend on that. We can just see that between the first and the second day the price was lowered by 10% and then by 20%. Therefore the answer will be 0.9*0.8=72%.

Therefore the option E is the answer. I dont see the reason to do the intermediate steps that other solutions propose. Its just adding math without needing it.
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Bunuel
The price of an item is discounted 10 percent on day 1 of a sale. On day 2, the item is discounted another 10 percent, and on day 3, it is discounted an additional 20 percent. The price of the item on day 3 is what percentage of the sale price on day 1?

A. 28%
B. 40%
C. 64.8%
D. 70%
E. 72%
\(100*\frac{90}{100}*\frac{90}{100}*\frac{80}{100}=64.8\)

Quote:
The price of the item on day 3 is what percentage of the sale price on day 1?

\(= \frac{64.80}{90}*100\)

\(= 72\), Answer must be (E)
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