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# The price of car A increased by 20 percent over the same time period

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Manager
Joined: 19 Nov 2009
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The price of car A increased by 20 percent over the same time period  [#permalink]

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28 Mar 2010, 16:28
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15% (low)

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84% (01:35) correct 16% (01:51) wrong based on 108 sessions

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The price of car A increased by 20 percent over the same time period that the price of car B decreased by 20 percent. The reduced price of car B was what percent of the original price of car A?

(1) The increased price of car A is equal to the original price of car B.
(2) The increase in price of car A was 5/6 the decrease in the price of car B.
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Joined: 20 Mar 2010
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Re: The price of car A increased by 20 percent over the same time period  [#permalink]

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28 Mar 2010, 18:01
1
If a and b are the original prices of car A and car B respectively
After the change their prices will be 1.2a and 0.8b
We need to find what percent of car A original price is the reduced price of car B i.e 0.8b/a *100

As per 1 increase price of car A is equal to the original price of car B i.e 1.2a=b from which we can calculate b/a and the required percentage so 1 alone is sufficient
As per 2 increase in price of car A was 5/6 the decrease in the price of car B i.e 0.2a = 5/6*(0.2b) from which we can calculate b/a and the required percentage so 2 alone is sufficient.

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Re: The price of car A increased by 20 percent over the same time period  [#permalink]

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29 Mar 2010, 02:43
First thought answer is A but agree with the explanation given by Crack700

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Re: The price of car A increased by 20 percent over the same time period  [#permalink]

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29 Mar 2010, 12:33
crack700 wrote:
If a and b are the original prices of car A and car B respectively
After the change their prices will be 1.2a and 0.8b
We need to find what percent of car A original price is the reduced price of car B i.e 0.8b/a *100

As per 1 increase price of car A is equal to the original price of car B i.e 1.2a=b from which we can calculate b/a and the required percentage so 1 alone is sufficient
As per 2 increase in price of car A was 5/6 the decrease in the price of car B i.e 0.2a = 5/6*(0.2b) from which we can calculate b/a and the required percentage so 2 alone is sufficient.

Good explanation . Answer would be D
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Location: Singapore
Concentration: Strategy, Finance
Re: The price of car A increased by 20 percent over the same time period  [#permalink]

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21 Jul 2017, 01:40
1
nsp007 wrote:
The price of car A increased by 20 percent over the same time period that the price of car B decreased by 20 percent. The reduced price of car B was what percent of the original price of car A?

(1) The increased price of car A is equal to the original price of car B.
(2) The increase in price of car A was 5/6 the decrease in the price of car B.

Car A = $x Car B =$ y

New Car A Price = $1.2x New Car B Price =$0.8y

z = $$\frac{(0.8y*100)}{x}$$
z = ?

1) 1.2x = y
$$\frac{y}{x}$$ = 1.2
Put this in z = $$\frac{(0.8y*100)}{x}$$ and we get the value of z.
z = 96%
Sufficient.

2) 0.2x = $$\frac{5}{6}$$*0.2y
$$\frac{y}{x}$$ = $$\frac{6}{5}$$
Put this in z = $$\frac{(0.8y*100)}{x}$$ and we get the value of z.
z = 96%
Sufficient.

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Re: The price of car A increased by 20 percent over the same time period   [#permalink] 21 Jul 2017, 01:40
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