Official Solution:The ratio of \(a\) to \(b\) is 1 to 2. If \(a\) is increased by \(x\%\) and \(b\) is decreased by \(\frac{x}{2}\%\), where \(x\neq 0\), which of the following represents the new ratio of \(a\) to \(b\)? A. \(\frac{100 + x}{200 - x}\)
B. \(\frac{1 + \frac{x}{100} }{1 - \frac{x}{200} }\)
C. \(\frac{x + 1}{2x + 2}\)
D. \(\frac{2x + 1}{200 - x}\)
E. \(\frac{200 + x}{1 - x}\)
The new ratio is:
\(\frac{1(1 + \frac{x}{100})}{2(1 - \frac{x}{200})} = \)
\(=\frac{1 + \frac{x}{100} }{2 - \frac{x}{100} } =\)
\(=\frac{\frac{100 + x}{100} }{\frac{200 - x}{100} } =\)
\(=\frac{100 + x}{100}* \frac{100}{200 - x} =\)
\(= \frac{100 + x}{200 - x}\).
Answer: A